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Program of Binary tree:
Btree::Btree(int O) : itemsInContainer(0)
{
finishInit(O);
}
Btree::~Btree(void)
if( root != 0 )
delete root;
void Btree::flush( DeleteType dt )
int oldValue = ownsElements();
ownsElements( delObj(dt) );
itemsInContainer = 0;
root = 0;
ownsElements( oldValue );
int Btree::hasMember( Object& o ) const
if( !o.isSortable() )
ClassLib_error( __ENOTSORT );
if( root == 0 )
return 0;
else
Node* loc;
int idx;
return root->found(&(Sortable&)o, &loc, &idx) != NOOBJECT;
Employ operator () instead of operator[]. While you have multiple subscripts, the cleanest way to do it is along with operator () instead of with operator[]. The reason is that
Rule: To determine the canonical form we should OR the min terms. A min term is defined as a Boolean equation of the input if the output is logic '1'. If the input is logic '1'
Explain the class invariant. - It's a condition that ensures correct working of a class and defines all the valid states for an object. - When an object is created class inv
algorithm
reocord of a student and a function ctotal to calculate the marks of any three subject by using ctotal() function
Overloading Binary Operators class SI {float i,p,n,r,a; public: SI(){}; SI(int gp,int gn, int gr); void putdata(void); SI operator+(SI); }; SI SI::opera
We can combine more than one variable on the same line i.e. float number1,number2,number3; etc Sometimes we want to mix the variable types used on the same line, this could
z = (a > b) ? a : b;
C program for function of average int average(int); void main() { int max=0,c=0; clrscr(); printf("ENTER THE LIMIT OF INPUT FOR AV
At a shop of marbles, packs of marbles are prepared. Packets are named A, B, C, D, E …….. All packets are kept in a VERTICAL SHELF in random order. Any numbers of packets with thes
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