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Now, let's get back to parabolas. There is a basic procedure we can always use to get a pretty good sketch of a parabola. Following it is.
1. Determine the vertex. We'll discuss how to determine this shortly. It's quite simple, but there are several methods for finding it and so will be discussed separately.
2. Find the y-intercept, (0, f (0)) .
3. Solve f ( x ) = 0 to determine the x coordinates of the x-intercepts if they exist.
4. Ensure that you've got at least one point to either side of the vertex. It is to ensure we get a somewhat accurate sketch. If the parabola contains two x-intercepts then already we'll have these points. If it contains 0 or 1 x-intercept we can either just plug in another x value or employ the y-intercept and the axis of symmetry to obtain the second point.
5. Sketch the graph. At this point we've gotten sufficient points to get a quite decent idea of what the parabola will look like.
Part A. relates to data representation and Part B. relates to Boolean logic. Part A. Data Representation The very first thing you need to do to begin Part A is to make
#question.P(x) = –x2 + 110x – 1,000. P(5), P(50), P(120) plot on graph
-3t^2+15t-18
An object 4.8 feet tall casts a shadow that is 14.4 feet long. How long in feet would the shadow be for an object which is 13.2 feet tall?
add - 3a + b - 10 -6c, c -d- a + 9 and - 4c +2a - 3b - 7
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Convert following into the form f (x ) = a ( x - h ) 2 + k Solution We are going to complete the square here. Though, it is a s
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Veronica''s family ordered 2 pizzas that cost $13.75 each and 2 pitchers of soda that cost $3.95 each. The total cost included a sales tax of 5.5%. They left 20% of the total cost
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