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Now, let's get back to parabolas. There is a basic procedure we can always use to get a pretty good sketch of a parabola. Following it is.
1. Determine the vertex. We'll discuss how to determine this shortly. It's quite simple, but there are several methods for finding it and so will be discussed separately.
2. Find the y-intercept, (0, f (0)) .
3. Solve f ( x ) = 0 to determine the x coordinates of the x-intercepts if they exist.
4. Ensure that you've got at least one point to either side of the vertex. It is to ensure we get a somewhat accurate sketch. If the parabola contains two x-intercepts then already we'll have these points. If it contains 0 or 1 x-intercept we can either just plug in another x value or employ the y-intercept and the axis of symmetry to obtain the second point.
5. Sketch the graph. At this point we've gotten sufficient points to get a quite decent idea of what the parabola will look like.
Solve (3x+ 1/ x + 4 ) ≥ 1. Solution The first thing that we have to do here is subtract 1 from both of sides and then get everything in a single rational expression. (3
Suppose that a company has a fixed cost of $150 per day and a variable cost of x^2+x. Further suppose that the revenue function is R(x) = xp and the price per unit is given by p =
-4/2+3i
change radical to an algebraic express with fractional exponets 5^x to the 3 power.
(x-y+z)2=
I have such a hard time understanding them
Prove that cosets of an ideal I in a ring R are disjoint or equal
what is the answer for this 2n+3n+7=-41
As the heading recommend here we will be solving quadratic equations by factoring them. Zero factor property or zero factor principle To solving quadric equation by factor
1. Kate ran 6 miles more than Peter ran. The sum of their distances is 28 miles. How far did Peter run? The domain of the solution is {0, 6, 11, 24}. a. Define your variable. b. Wr
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