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Now, let's get back to parabolas. There is a basic procedure we can always use to get a pretty good sketch of a parabola. Following it is.
1. Determine the vertex. We'll discuss how to determine this shortly. It's quite simple, but there are several methods for finding it and so will be discussed separately.
2. Find the y-intercept, (0, f (0)) .
3. Solve f ( x ) = 0 to determine the x coordinates of the x-intercepts if they exist.
4. Ensure that you've got at least one point to either side of the vertex. It is to ensure we get a somewhat accurate sketch. If the parabola contains two x-intercepts then already we'll have these points. If it contains 0 or 1 x-intercept we can either just plug in another x value or employ the y-intercept and the axis of symmetry to obtain the second point.
5. Sketch the graph. At this point we've gotten sufficient points to get a quite decent idea of what the parabola will look like.
what is t
if A is an ideal and phi is onto S,then phi(A)is an ideal.
Nel skates at 18 mph and and Christine skates at 22 mph if they can keep up that pace for 4.5 hours how far will they be a part at the end of the time
x plus 6 equal -10
the set of data shows of score of 25 students in their periodical test. 34 35 40 40 48 21 20 19 34 45 19 17 18 15 16 21 20 18 17 10 19 17 29 45 50 1. what score is typical t
9x^4-x^2-12x-36
solve x+4y=8 2x+5y=7
What do you have to do to be able to answer any problem solving questions (relating to or concerning algebra)?
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how to answer
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