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Now, let's get back to parabolas. There is a basic procedure we can always use to get a pretty good sketch of a parabola. Following it is.
1. Determine the vertex. We'll discuss how to determine this shortly. It's quite simple, but there are several methods for finding it and so will be discussed separately.
2. Find the y-intercept, (0, f (0)) .
3. Solve f ( x ) = 0 to determine the x coordinates of the x-intercepts if they exist.
4. Ensure that you've got at least one point to either side of the vertex. It is to ensure we get a somewhat accurate sketch. If the parabola contains two x-intercepts then already we'll have these points. If it contains 0 or 1 x-intercept we can either just plug in another x value or employ the y-intercept and the axis of symmetry to obtain the second point.
5. Sketch the graph. At this point we've gotten sufficient points to get a quite decent idea of what the parabola will look like.
Which of the following is a solution to the inequality y A.) (1,1) B.) (3,0) C.) (-3, 10) D.) (0,0)
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Fact Following any system of equations there are accurately three possibilities for the solution. 1. There will not be a solution. 2. There will be just one solution.
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The point in graph to the right are (1998),177),(20087),(2002,195 and (2004,207)where the y coordinates are the thousands complete part(a)and (b)(a use the first and last data poin
Solve following equations. (a) x 2 -100 = 0 (b) 25 y 2 - 3 = 0 Solution There actually isn't all that much to these problems. To use the square root property a
I am a 14 year old 9th grade Freshmen, I seriously need help. I am failing with a 49.00 grade in my class
Domain and Range The domain of any equation is the set of all x's which we can plug in the equation & get back a real number for y. The range of any equation is the set of all
81x^5-49x^3=0
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