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Now, let's get back to parabolas. There is a basic procedure we can always use to get a pretty good sketch of a parabola. Following it is.
1. Determine the vertex. We'll discuss how to determine this shortly. It's quite simple, but there are several methods for finding it and so will be discussed separately.
2. Find the y-intercept, (0, f (0)) .
3. Solve f ( x ) = 0 to determine the x coordinates of the x-intercepts if they exist.
4. Ensure that you've got at least one point to either side of the vertex. It is to ensure we get a somewhat accurate sketch. If the parabola contains two x-intercepts then already we'll have these points. If it contains 0 or 1 x-intercept we can either just plug in another x value or employ the y-intercept and the axis of symmetry to obtain the second point.
5. Sketch the graph. At this point we've gotten sufficient points to get a quite decent idea of what the parabola will look like.
square root 18x^7y^5
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1 and 2 are supplementary and 1 = 72 find 2
(-3) EVALUATE X3 -2X2 + 6X -64
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4 __ -3 4
2x+2=2 then x value?
Sketch the graph through the process of finding the zeroes Example Sketch the graph of P ( x ) = x 4 - x 3 - 6x 2 . Solution
5x - y = 1 -15x +4y = 6
Coordinates for the point The listed first number is the x-coordinate of the point and the second number listed is the y-coordinate of the point. The ordered pair for any spec
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