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Now, let's get back to parabolas. There is a basic procedure we can always use to get a pretty good sketch of a parabola. Following it is.
1. Determine the vertex. We'll discuss how to determine this shortly. It's quite simple, but there are several methods for finding it and so will be discussed separately.
2. Find the y-intercept, (0, f (0)) .
3. Solve f ( x ) = 0 to determine the x coordinates of the x-intercepts if they exist.
4. Ensure that you've got at least one point to either side of the vertex. It is to ensure we get a somewhat accurate sketch. If the parabola contains two x-intercepts then already we'll have these points. If it contains 0 or 1 x-intercept we can either just plug in another x value or employ the y-intercept and the axis of symmetry to obtain the second point.
5. Sketch the graph. At this point we've gotten sufficient points to get a quite decent idea of what the parabola will look like.
Two cars are 500 miles apart & directly moving towards each other. One car is at a speed of 100 mph and the other is at 70 mph. Supposing that the cars start at the same time how
what is 6(5*-6)
square root of 18
Example : Solve (x+ 1 / x - 5 )≤ 0 . Solution Before we get into solving these we need to point out that these don't solve in the similar way which we've solve equations
#question.P(x) = –x2 + 110x – 1,000. P(5), P(50), P(120) plot on graph
#can u tell me some things on rigid and non rigid transformations
5x + 2y = 6 -2x + y = -6
Maximise, p =168x+161y+158z+132w 475x+450y+440z+438w 250x+230y+220z+210w 119x+115.5y+114.8z+112.25w 160x+50y+120z+50w 12x+8.8y+7.4z+5.3w x >=4
40x-30y=15 x+50y=-25
turn into an inequality expression, y= (0,330) x= (110,0)
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