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Now, let's get back to parabolas. There is a basic procedure we can always use to get a pretty good sketch of a parabola. Following it is.
1. Determine the vertex. We'll discuss how to determine this shortly. It's quite simple, but there are several methods for finding it and so will be discussed separately.
2. Find the y-intercept, (0, f (0)) .
3. Solve f ( x ) = 0 to determine the x coordinates of the x-intercepts if they exist.
4. Ensure that you've got at least one point to either side of the vertex. It is to ensure we get a somewhat accurate sketch. If the parabola contains two x-intercepts then already we'll have these points. If it contains 0 or 1 x-intercept we can either just plug in another x value or employ the y-intercept and the axis of symmetry to obtain the second point.
5. Sketch the graph. At this point we've gotten sufficient points to get a quite decent idea of what the parabola will look like.
How do you simplfly 25 and 15 if u say 5 and the teacher thinks it''s wrong?
If you sell a kayak for $400 and your sales per day averages $5200. Assume the sales per day is a linear function of price of kayak. write an equation describing the relationship.
I am trying to find the answer to y=x^2+12x-11 Would you help me
graphing linear programs
what is 10037+3443=
.
5x+2x-17=53
Also, as x obtain very large, both positive & negative, the graph approaches the line specified by y = 0 . This line is called a horizontal asymptote. Following are the genera
6x^3+3x^2-18x
We have to give one last note on interval notation before moving on to solving inequalities. Always recall that while we are writing down an interval notation for inequality that t
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