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Now, let's get back to parabolas. There is a basic procedure we can always use to get a pretty good sketch of a parabola. Following it is.
1. Determine the vertex. We'll discuss how to determine this shortly. It's quite simple, but there are several methods for finding it and so will be discussed separately.
2. Find the y-intercept, (0, f (0)) .
3. Solve f ( x ) = 0 to determine the x coordinates of the x-intercepts if they exist.
4. Ensure that you've got at least one point to either side of the vertex. It is to ensure we get a somewhat accurate sketch. If the parabola contains two x-intercepts then already we'll have these points. If it contains 0 or 1 x-intercept we can either just plug in another x value or employ the y-intercept and the axis of symmetry to obtain the second point.
5. Sketch the graph. At this point we've gotten sufficient points to get a quite decent idea of what the parabola will look like.
a mixture of 45g of salt and 29g of banking soda is poured in 370ml of water. What is the total of mass of the mixture in grams?
Actually here we're not going to look at a general cubic polynomial. Here we are jsut going to look at f ( x ) = x 3 . Really there isn't much to do here other than only plugging
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Using transformation sketch the graph of each of the following. g ( x ) = - x 2 Solution (a) Depending on the placement of
Multiply a Row by a Constant. In this operation we multiply row i by a constant c and the notation will utilizes here is cR i . Note that we can also divide a row by a constant
We should graph a couple of these to make sure that we can graph them as well. Example : Sketch the graph of the following piecewise function. Solution Now while w
1/x+10>0 what is the solution set
What is the effectiveness of new math?
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