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Now, let's get back to parabolas. There is a basic procedure we can always use to get a pretty good sketch of a parabola. Following it is.
1. Determine the vertex. We'll discuss how to determine this shortly. It's quite simple, but there are several methods for finding it and so will be discussed separately.
2. Find the y-intercept, (0, f (0)) .
3. Solve f ( x ) = 0 to determine the x coordinates of the x-intercepts if they exist.
4. Ensure that you've got at least one point to either side of the vertex. It is to ensure we get a somewhat accurate sketch. If the parabola contains two x-intercepts then already we'll have these points. If it contains 0 or 1 x-intercept we can either just plug in another x value or employ the y-intercept and the axis of symmetry to obtain the second point.
5. Sketch the graph. At this point we've gotten sufficient points to get a quite decent idea of what the parabola will look like.
(4y2)(2y)
coffee was 2.50 yesterday and 2.85 today. what percent did it go up?
It is probably the easiest function which we'll ever graph and still it is one of the functions which tend to cause problems for students. The most general form for the constant
x3+y3/x+y
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Solve: 3/x+2 less tan or equal to 4
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.what is the average rate of change if f(x) = 4x + 6 .
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