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Now, let's get back to parabolas. There is a basic procedure we can always use to get a pretty good sketch of a parabola. Following it is.
1. Determine the vertex. We'll discuss how to determine this shortly. It's quite simple, but there are several methods for finding it and so will be discussed separately.
2. Find the y-intercept, (0, f (0)) .
3. Solve f ( x ) = 0 to determine the x coordinates of the x-intercepts if they exist.
4. Ensure that you've got at least one point to either side of the vertex. It is to ensure we get a somewhat accurate sketch. If the parabola contains two x-intercepts then already we'll have these points. If it contains 0 or 1 x-intercept we can either just plug in another x value or employ the y-intercept and the axis of symmetry to obtain the second point.
5. Sketch the graph. At this point we've gotten sufficient points to get a quite decent idea of what the parabola will look like.
x-2y = z for y
28,14...is the sequence arithmetic or geometric?
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Sabrina invested 1500000 in stocks and bonds.Her investment in bonds is 5000 more than half her investment in stocks.How much did she invest in each ?
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Hi everyone, needing help with these math questions. Please include your workings out so I can understand how you got your answers,thanks! INTRO: Three friends have been training
Dependent system example Example: Solve the given system of equations. 2x + 5 y = -1 -10x - 25 y = 5 Solution In this instance it looks like elimination would b
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