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Now, let's get back to parabolas. There is a basic procedure we can always use to get a pretty good sketch of a parabola. Following it is.
1. Determine the vertex. We'll discuss how to determine this shortly. It's quite simple, but there are several methods for finding it and so will be discussed separately.
2. Find the y-intercept, (0, f (0)) .
3. Solve f ( x ) = 0 to determine the x coordinates of the x-intercepts if they exist.
4. Ensure that you've got at least one point to either side of the vertex. It is to ensure we get a somewhat accurate sketch. If the parabola contains two x-intercepts then already we'll have these points. If it contains 0 or 1 x-intercept we can either just plug in another x value or employ the y-intercept and the axis of symmetry to obtain the second point.
5. Sketch the graph. At this point we've gotten sufficient points to get a quite decent idea of what the parabola will look like.
14th term 60,68,76,84,92
I am trying to figure out this answer f(x) = -3/4x + 4. but think I am getting it all wrong
2x-y=-1
how to simplifie radicals
1/p+1/q+1/x=1/p+q+x find x
i cant figure this out
y+5=(4x+1)
Michael bought three USB flash drives each capacity of 1.5 gigabytes.He also bought two USB flash drives each with a capacity of @ gigabytes.Express the total capacity of the three
Compounded semiannually P dollars is invested at annual interest rate r for 1 year. If the interest is compounded semiannually, then the polynomial P(1 + r/2)^2 represents the valu
How do i find a equation for a line with slope of -4 and x-intercept of 6?
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