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Now, let's get back to parabolas. There is a basic procedure we can always use to get a pretty good sketch of a parabola. Following it is.
1. Determine the vertex. We'll discuss how to determine this shortly. It's quite simple, but there are several methods for finding it and so will be discussed separately.
2. Find the y-intercept, (0, f (0)) .
3. Solve f ( x ) = 0 to determine the x coordinates of the x-intercepts if they exist.
4. Ensure that you've got at least one point to either side of the vertex. It is to ensure we get a somewhat accurate sketch. If the parabola contains two x-intercepts then already we'll have these points. If it contains 0 or 1 x-intercept we can either just plug in another x value or employ the y-intercept and the axis of symmetry to obtain the second point.
5. Sketch the graph. At this point we've gotten sufficient points to get a quite decent idea of what the parabola will look like.
x/2+6=3+2x
has a y-intercept of 5 and a slope of 2/3. solve for the standard equation
Sketch the graph of f ( x ) = ( x -1) 3 + 1 . Solution Now, as we talked regarding while we first looked at graphing earlier in
Two cars are 500 miles apart & directly moving towards each other. One car is at a speed of 100 mph and the other is at 70 mph. Supposing that the cars start at the same time how
(-9/8-8/9)- (-9/8-9)
In his boat, Leonard can travel 24 miles upstreamin the same time it takes to travel 36 miles downstream
Now let's move into the next technique for solving systems of equations. As we illustrated in the example the method of substitution will frequently force us to deal with fraction
what is t
Find the following product (-4)(-2)(5)=
-2
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