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Now, let's get back to parabolas. There is a basic procedure we can always use to get a pretty good sketch of a parabola. Following it is.
1. Determine the vertex. We'll discuss how to determine this shortly. It's quite simple, but there are several methods for finding it and so will be discussed separately.
2. Find the y-intercept, (0, f (0)) .
3. Solve f ( x ) = 0 to determine the x coordinates of the x-intercepts if they exist.
4. Ensure that you've got at least one point to either side of the vertex. It is to ensure we get a somewhat accurate sketch. If the parabola contains two x-intercepts then already we'll have these points. If it contains 0 or 1 x-intercept we can either just plug in another x value or employ the y-intercept and the axis of symmetry to obtain the second point.
5. Sketch the graph. At this point we've gotten sufficient points to get a quite decent idea of what the parabola will look like.
Solve following equations by factoring. a) x 2 - x = 12 b) y 2 + 12 y + 36 = 0 Solution a) x 2 - x = 12 First to solve it get everything on si
As a last topic in this section we have to briefly talk about how to take a parabola in the general form & convert it into the following form
1/x+10>0 what is the solution set
10000000004*56464684654654
I am a first time algebra student and am confused. Can you give me step by step equations on how to calculate 5+2x=2x+6
If x+y=7 and xy=10 find x2+y2
10x^7y^3 and 25xv^8y^4
12 X 6 = FIND THE ESTIMATE AND RECCORD THE PRODUCT
Im an 8th grader and my grades arent the best. Im really having trouble with slope. I just dont get it all that well.
a mixture of 45g of salt and 29g of banking soda is poured in 370ml of water. What is the total of mass of the mixture in grams?
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