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Now, let's get back to parabolas. There is a basic procedure we can always use to get a pretty good sketch of a parabola. Following it is.
1. Determine the vertex. We'll discuss how to determine this shortly. It's quite simple, but there are several methods for finding it and so will be discussed separately.
2. Find the y-intercept, (0, f (0)) .
3. Solve f ( x ) = 0 to determine the x coordinates of the x-intercepts if they exist.
4. Ensure that you've got at least one point to either side of the vertex. It is to ensure we get a somewhat accurate sketch. If the parabola contains two x-intercepts then already we'll have these points. If it contains 0 or 1 x-intercept we can either just plug in another x value or employ the y-intercept and the axis of symmetry to obtain the second point.
5. Sketch the graph. At this point we've gotten sufficient points to get a quite decent idea of what the parabola will look like.
using the formula for the difference between two squares,factor the following : 5-x
We'll begin this section by defining just what a root or zero of a polynomial is. We say that x = r is a root or zero of a polynomial, P ( x) , if P ( r )= 0 . In other terms x=
the parking lot will have an area of 160 square meters.The shorter base is 4m longer than the height of the trapezoid,and the longer base is 8m longer than the height.What is the l
I am a first time algebra student and am confused. Can you give me step by step equations on how to calculate 5+2x=2x+6
(2 X2)3 BY BB
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5x + 2y = 6 -2x + y = -6
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