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Now, let's get back to parabolas. There is a basic procedure we can always use to get a pretty good sketch of a parabola. Following it is.
1. Determine the vertex. We'll discuss how to determine this shortly. It's quite simple, but there are several methods for finding it and so will be discussed separately.
2. Find the y-intercept, (0, f (0)) .
3. Solve f ( x ) = 0 to determine the x coordinates of the x-intercepts if they exist.
4. Ensure that you've got at least one point to either side of the vertex. It is to ensure we get a somewhat accurate sketch. If the parabola contains two x-intercepts then already we'll have these points. If it contains 0 or 1 x-intercept we can either just plug in another x value or employ the y-intercept and the axis of symmetry to obtain the second point.
5. Sketch the graph. At this point we've gotten sufficient points to get a quite decent idea of what the parabola will look like.
I am trying to figure out how the tree method works for number 47
HOW DOES Log0.5 16 =4
0.06n=0.15
Simpler method Let's begin by looking at the simpler method. This method will employ the following fact about exponential functions. If b x = b y then x
This section doesn't actually have many to do with the rest of this chapter, but since the subject required to be covered and it was a fairly short chapter it appeared like as good
what is 93%10
15+1/2x=0.60(20+x)
Describe the property used to convert the equation from one line to the next: 8y-(8+6y)=20
i dont want the answer but how i shouuld find the answer plz :A rectangular display case houses a square pyramid. Both have the same square base measuring x inches on a side. The t
A tank is filling with water from a natural spring. Two days ago the water was 10 feet deep, and yesterday the water was 12 feet deep. Assume that the water depth continues to rise
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