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Now, let's get back to parabolas. There is a basic procedure we can always use to get a pretty good sketch of a parabola. Following it is.
1. Determine the vertex. We'll discuss how to determine this shortly. It's quite simple, but there are several methods for finding it and so will be discussed separately.
2. Find the y-intercept, (0, f (0)) .
3. Solve f ( x ) = 0 to determine the x coordinates of the x-intercepts if they exist.
4. Ensure that you've got at least one point to either side of the vertex. It is to ensure we get a somewhat accurate sketch. If the parabola contains two x-intercepts then already we'll have these points. If it contains 0 or 1 x-intercept we can either just plug in another x value or employ the y-intercept and the axis of symmetry to obtain the second point.
5. Sketch the graph. At this point we've gotten sufficient points to get a quite decent idea of what the parabola will look like.
omar loves bags of potato chips and ice cream bars, and they have fat and calories as follows: bags of potato chips contain 12 grams of fat and 325 calories; ice cream bars contain
There are also two lines on each of the graph. These lines are called asymptotes and as the graphs illustrates as we make x large (in both the +ve and -ve sense) the graph of the h
-2
what is the principal square root of the square number?
how do I write 4x^3-62 in descending order
6-5+3h*5h
(2,9);y=3x-1
What do you have to do to be able to answer any problem solving questions (relating to or concerning algebra)?
2 adults for 10 children and 3 adults for 12 children
if x=7 an y=9 and the answer is 98 what is the expresson?
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