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Now, let's get back to parabolas. There is a basic procedure we can always use to get a pretty good sketch of a parabola. Following it is.
1. Determine the vertex. We'll discuss how to determine this shortly. It's quite simple, but there are several methods for finding it and so will be discussed separately.
2. Find the y-intercept, (0, f (0)) .
3. Solve f ( x ) = 0 to determine the x coordinates of the x-intercepts if they exist.
4. Ensure that you've got at least one point to either side of the vertex. It is to ensure we get a somewhat accurate sketch. If the parabola contains two x-intercepts then already we'll have these points. If it contains 0 or 1 x-intercept we can either just plug in another x value or employ the y-intercept and the axis of symmetry to obtain the second point.
5. Sketch the graph. At this point we've gotten sufficient points to get a quite decent idea of what the parabola will look like.
3x+y=-2 6x+2y=10
Solve following. |3x + 2| Solution Now we know that p ≥ 0 and thus can't ever be less than zero. Hence, in this case there is no solution as it is impos
the sudbrook school play has a maximum of 700 tickets to sell.at least 300 tickets must be sold in advance. Advance tickets will be sold for $20.00 while the tickeys at the door wi
2.48=0.3x
I really need help in this question (-5d + 1)(-2) I am really confused
how to solve the sum of a polynomials
I need to relearn algebra1and 2 please help me!i have got to I cant get this job because I forgot how to do algebra 1 and 2
how would you divide a negative fraction with a positve fraction
Now let's move into the next technique for solving systems of equations. As we illustrated in the example the method of substitution will frequently force us to deal with fraction
How do I do this?? x/x+1=x/2(x-4)
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