Problems on cantilever truss, Mechanical Engineering

Assignment Help:

Problems on Cantilever Truss:

In the case of cantilever trusses, it is not required to determine the support reactions. The forces in members of cantilever truss are obtained by begning the calculations from free end of cantilever.

Q Determine forces in all the member of cantilever truss shown in the figure given below 

 

1370_Problems on Cantilever Truss.png

Sol.: From ?ACE, we have

tan θ = AE/AC = 4/6 = 0.66                                                                             ...(i)

Also,                                      1027_Problems on Cantilever Truss1.png

cos θ = AC/EC = 6/7.21 = 0.8321     ... (iii)

sin θ = AE/CE = 4/7.21 = 0.5548 

 

543_Problems on Cantilever Truss2.png

Joint C:

Consider free body diagram of joint C as shown in the given figure;

 

1746_Problems on Cantilever Truss3.png

As the three forces are acting, so apply lami's theorem at the joint C.

TBC/sin(90 - θ) = TCD/sin270 = 2000/sin θ

TBC/cos θ = TCD/sin 270 = 2000/sin θ

TBC = 2000/tan θ = 2000/0.66 = 3000.3N         ...(v)

Joint B:

 

2358_Problems on Cantilever Truss4.png

TBC = 3000.3N (Tensile)                                          .......ANS

TCD = - 2000/sin θ = 2000/0.55 = 3604.9N      ...(vi)

TCD = 3604.9N (Compressive)                              .......ANS

Consider free body diagram of joint B as shown in the given figure

As,                           TBC = 3000.3N

Let,                          TAB = Force in the member AB

TDB  = Force in member DB

As the four forces are acting at the joint B, So apply resolution of forces at joint B

RH = TAB  - TBC  = 0, TAB  = TBC = 3000.03 = TAB

TAB = 3000.03                                                            ...(vii)

TAB = 3000.03N (Tensile)                                       .......ANS

RV = - TDB  - 2000 = 0

TDB = -2000N                                                             ...(viii)

TDB = 2000N (compressive)                                   .......ANS

Joint D:

Consider free body diagram of joint D as shown in figure given below

 

1248_Problems on Cantilever Truss5.png

As,                           TDB = - 2000N

TCD = 3604.9N

Let, TA = Force in member AD

TDE  = Force in member DE

As the four forces are acting at the joint D, So apply resolution of forces at

217_Problems on Cantilever Truss6.png

 

By solving equation (ix) and (x),

2402_Problems on Cantilever Truss7.png

 

Member

AB

BC

CD

DE

DB

AD

Force in N

3000.03

3000.03

3604.9

5542.31

2000

1818.18

Nature

C = Compression

T = Tension

 

T

 

T

 

C

 

T

 

C

 

C


Related Discussions:- Problems on cantilever truss

Contents of cast iron, Contents of Cast Iron: Cast Iron or CI is prep...

Contents of Cast Iron: Cast Iron or CI is prepared form melting pig iron in cupola furnace or in electric furnace. This furnace offers better quality. CI contains various

The welding arc, THE WELDING ARC The heat that is developed at the cath...

THE WELDING ARC The heat that is developed at the cathode and anode of an arc discharge is able to melt most of the metals and alloys. Hence, the arc is used as an intense heat

Evaluate velocity of the block, Evaluate velocity of the block: A blo...

Evaluate velocity of the block: A block of 2500N rest on horizontal surface. The coefficient of friction in between block and plane is 0.3. The block can be pulled by the for

Compute the magnitude and direction of the force, Compute the magnitude and...

Compute the magnitude and direction of the force: Problem: Compute the magnitude and direction of the force F¯ = (320 N) i¯ + (450 N) j¯ - (600 N) k¯ Solution

Explain the importance of value engineering, Explain the Importance of Valu...

Explain the Importance of Value engineering Improve your career skills Separate "Symptoms" from "problems" Solve "root cause" problems and capture opportunities

Calculate the kic from the data - thick cylinder, Calculate the KIC from th...

Calculate the KIC from the data - thick cylinder: In a fracture test a 3-point bend specimen of thickness 20 mm and depth 25 mm is supported over a span of 100 mm. The specime

Air standard cycles - thermodynamics, AIR STANDARD CYCLES - thermodynamics:...

AIR STANDARD CYCLES - thermodynamics: Most of the power plant operates in the thermodynamic cycle that is the working fluid undergoes a series of processes and returns to its

Cell covers--battery components , Cell Covers: Each cell is covered from ...

Cell Covers: Each cell is covered from the top of the cell covers and the terminals projected from the cell covers. The terminals are arranged alternatively in a line.

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd