Problem type-aspects of scheduling , Mechanical Engineering

Assignment Help:

Problem Type

Aforementioned illustration relates to the class of non-cyclic scheduling problems characterized via the subsequent features.

(a) The Flexible Manufacturing System consists of M stations (workplaces, machines) all of that can process at mainly one operation at a time,

(b) The inventory that may change at some time contains N jobs along with termed earliest possible beginning times and due dates,

(c) A job is a sequence of operations along with precedence constraints that is most operations can only be begun if one or some preceding operations have been finished.

                            Table no.2 (b): Due Dates Distributions for Situation E-H

Situation A : Case 2, 30% late jobs under the FIFO scheduling rule

Demanded Throuhput Time       %          of

Parts

 

240                            5

 

480                            5

 

720                            5

 

960                            35

 

1200                          50

 

Average Throughput Time: 1008 min

 

Demanded/achieved flow factor: 1.20

 

Situation A : Case 2, 50% late jobs under the FIFO scheduling rule

Demanded Throughput Time     %          of

Parts

 

240                            5

 

480                            10

 

720                            35

 

960                            27

 

1200                          23

 

Average Throughput Time: 847 min

 

Demanded/achieved flow factor: 1.00

 

Situation A : Case 2, 70% late jobs under the FIFO scheduling rule

Demanded Throuhput Time       %          of

Parts

 

240                            19

 

480                            25

 

720                            31

 

960                            15

 

1200                          10

 

Average Throughput Time: 653 min

 

Demanded/achieved flow factor: 0.78

 

Situation A : Case 2, 85% late jobs under the FIFO scheduling rule

Demanded Throuhput Time       %          of

Parts

 

240                            30

 

480                            45

 

720                            15

 

960                            5

 

1200                          5

 

Average Throughput Time: 504 min

 

Demanded/achieved flow factor: 0.60

 

(d) For all operation, this is identify that on which stations (one or more) this can be represented and how long this acquires (containing transportation times); these durations  are  supposed  to  be  independent of  the  scheduling deterministic and policy  ,

(e) Operations which have been begun but cannot be interrupted (non-preemptive scheduling), and

(f) The idle times among the operations are not limited, neither are the buffers opposite the stations or at the output.

Consequently the major restriction is the capability of the stations. Another limitation is assumed to be of secondary significance. They may be shown via the earliest possible starting times of the operations or contained in the operation times, for instants: via adding a constant average transportation delay. Obviously, the transportation system can be integrated via adding transport operations to the work plans and explaining one or more resources that provide transport and have to be assigned as well. The only limit implied through the  assumptions made  is  that  the  resource  uses  times  are  independent of  the processing sequences.

In the test difficulty, the options on which station an operation is presented are only amongst identical stations.  Hence,  for  each  operation  there  is  merely  one  value  for  its (nominal)  net  operation  time.  However, this assumption is not essential for the algorithms discussed afterward.


Related Discussions:- Problem type-aspects of scheduling

Explain screed unit, Explain the Screed unit The main screed is pivoted...

Explain the Screed unit The main screed is pivoted at the centre point of the machine to assure a constant flatness of work on uneven grounds. It consists of 2440 mm main scree

Evaluate the acceleration of the three weights, Evaluate the acceleration o...

Evaluate the acceleration of the three weights: A system of weight connected by the string passing over pulleys A and B is shown in figure given below. Find out acceleration

Compute the displacement of the particle, Compute the displacement of the p...

Compute the displacement of the particle: The acceleration time diagram for particle is as specified below .Computed velocity of the particle at several time intervals, plot v

Find the velocity and acceleration of the slider, Question: The disk 3 ...

Question: The disk 3 shown in the figure rotates at a constant angular velocity ω 3 = 2.0 rad/s. A slider in a slot in the disk causes rod 2 to rotate.  When the slider is

V-block and clamp - angle projection drawing, A V-block clamp consists of 3...

A V-block clamp consists of 3 components, a V-block, yoke and clamping screw.  Using a rule, measure the sketches below and produce a 3rd angle projection drawing for each componen

Back Rake Angle, Why is back rake angle preferred to be negative for brittl...

Why is back rake angle preferred to be negative for brittle materials?

Computer integrated manufacturing, the component of computer integrated man...

the component of computer integrated manufacturing with the diagram

Applications of co2 welding, APPLICATIONS OF CO 2 WELDING CO 2 weldin...

APPLICATIONS OF CO 2 WELDING CO 2 welding is extremely useful for joining thin sheets of thickness range 1.0 to 2.0 mm because it is possible to keep the heat input low to av

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd