Probability of chosen number from 1st 500 divisble by 3or5 , Mathematics

Assignment Help:

IN THIS WE HAVE TO ADD THE PROBABILITY of 3 and 5 occuring separtely and subtract prob. of 3 and 5 occuring together therefore p=(166+100-33)/500=233/500=0.466

Related Discussions:- Probability of chosen number from 1st 500 divisble by 3or5

Life mathametics, 20% of the total quantity of oil is 40 litres find the to...

20% of the total quantity of oil is 40 litres find the total quantity of oil in litres

Marketig research report , need help to write Marketing research reprot abo...

need help to write Marketing research reprot about IBM company using spss (statistical program) to analys the given data about the company and write the report according to given i

Trigonometric functions, -cot^2 90^0 + 4 sin 270^0 - 3 tan 180^0

-cot^2 90^0 + 4 sin 270^0 - 3 tan 180^0

Marketing research, Discuss the role research would play during your decisi...

Discuss the role research would play during your decision making

How many dollars did they raise the first two days, The freshman class is p...

The freshman class is participating in a fundraiser. Their target is to raise $5,000. After the first two days of the fundraiser, they have raised 32 percent of their goal. How man

Step functions, Before going to solving differential equations we must see ...

Before going to solving differential equations we must see one more function. Without Laplace transforms this would be much more hard to solve differential equations which involve

Construction , construct of tangents a circle from an external point when ...

construct of tangents a circle from an external point when its centre is not known

Example of distributive law, Maya gives the children examples of distributi...

Maya gives the children examples of distributive with small numbers initially, and leads them towards discovering the law. The usual way she does this is to give the children probl

3/7/2013 6:18:48 AM s= {1,2,3 ................ 499,500} n(A) = 500/3 = maximum 166 so probability divided by 3 is p(A) = 166/500 n(B) = 500/5 = maximum 100 so probability divided by 5 is p(A) = 10/500 n(A and B) = maximum 33 so probability divided by both 3 and 5 is p(A and B )= 33/500 p(A or B) = p(A)+P(B)-p(A and B) p(A or B) = (166/500)+(100/500)-(33/500) = 233/500

3/7/2013 6:18:48 AM

s= {1,2,3 ................ 499,500}

n(A) = 500/3 = maximum 166 so probability divided by 3 is p(A) = 166/500

n(B) = 500/5 = maximum 100 so probability divided by 5 is p(A) = 10/500

n(A and B) = maximum 33 so probability divided by both 3 and 5 is p(A and B )= 33/500

p(A or B) = p(A)+P(B)-p(A and B)

p(A or B) = (166/500)+(100/500)-(33/500) = 233/500

Write Your Message!

Name

Email id

Message

Verfication Code

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

Submit Assignment

User Account

All Pages