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IN THIS WE HAVE TO ADD THE PROBABILITY of 3 and 5 occuring separtely and subtract prob. of 3 and 5 occuring together therefore p=(166+100-33)/500=233/500=0.466
altitude 35000 @ 9:30 9;42 alt 17500 increase speed by factor of 3 level out at 2500= how much time will it take
a drawn picture on a graph that includes equations of each line
Question: All rates should be calculated to 3 decimal places in % (e.g. 1.234%), the discount factors to 5 decimal places (e.g. 0.98765), and the bond prices to 3 decimal place
Ashow that sec^2x+cosec^2x cannot be less than 4
Mike sells on the average 15 newspapers per week (Monday – Friday). Find the probability that 2.1 In a given week he will sell all the newspapers [7] 2.2 In a given day he will sel
Tetracycline 500 mg capsules Sig: 1 cap po bid for 14 days. Refills: 2 What is the dose of this medication:____________________ (0.5 point) How many doses are given per day:______
6987+746-212*7665
Example : Determine the equation of the line which passes through the point (8, 2) and is, parallel to the line given by 10 y+ 3x = -2 Solution In both of parts we are goi
Consider the subsequent IVP. y' = f(t,y) , y(t 0 ) = y 0 If f(t,y) and ∂f/∂y are continuous functions in several rectangle a o - h o + h which is included in a
Evaluate each of the following. (a) 25 1/2 (b) 32 1/5 Solution (a) 25 1/2 Thus, here is what we are asking in this problem. 2
s= {1,2,3 ................ 499,500}n(A) = 500/3 = maximum 166 so probability divided by 3 is p(A) = 166/500n(B) = 500/5 = maximum 100 so probability divided by 5 is p(A) = 10/500n(A and B) = maximum 33 so probability divided by both 3 and 5 is p(A and B )= 33/500p(A or B) = p(A)+P(B)-p(A and B)p(A or B) = (166/500)+(100/500)-(33/500) = 233/500
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