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how can i solve it
Find the value of p and q for which the system of equations represent coincident lines 2x +3y = 7, (p+q+1)x +(p+2q+2)y = 4(p+q)+1 Ans: a 1 = 2, b 1 = 3, c 1 = 7 a 2 =
Solve by factorization X 2 +(a/a+b + a+b/a)x+1 = 0 X 2 +(a/a+b + a+b/a)x+1 => X 2 +(a/a+b x a+b/ax + a/a+b .a+b/a) => X[x+a/a+b] +a+b/a[a+a*a+b]= 0 => X= -a
56+3
Example Factorize x 2 - 4x + 4. If we substitute x = 1, the value of the expression will be (1) 2 - 4(1) + 4 = 1 If we substitute x = -1, the value o
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