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A man is known to speak truth 3 out of 4 times.He throws adie and reports it is a six. Find the probability that it is actually a six.
Solution) we can get a six if a man says truth =3/4*1/6
or when he lies and it is not a six=1/4*5/6
so by bayes theorem=3/4*1/6 div by 1/4*5/6+3/4*1/6=3/8
-9+f ?-1 ?? (a-1)=-12 f(-3)=2
When finding the limit as x approaches 0 the for function (square root of x^3 + x^2) cos(pi/2x) would the limit not exist because there would be a zero in the denominator?
63*789
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1. Construct a grammar G such that L(G) = L(M) where M is the PDA in the previous question. Then show that the word aaaabb is generated by G. 2. Prove, using the Pumping Lemma f
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