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A man is known to speak truth 3 out of 4 times.He throws adie and reports it is a six. Find the probability that it is actually a six.
Solution) we can get a six if a man says truth =3/4*1/6
or when he lies and it is not a six=1/4*5/6
so by bayes theorem=3/4*1/6 div by 1/4*5/6+3/4*1/6=3/8
One of the well-known class of models that involve a simple difference equation are models of mean reversion. These models typically take the form yt+1 - yt = -a(yt - μ)where 0
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is 1 a prime number?
v=u+at s=ut+1/2at^2
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