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A man is known to speak truth 3 out of 4 times.He throws adie and reports it is a six. Find the probability that it is actually a six.
Solution) we can get a six if a man says truth =3/4*1/6
or when he lies and it is not a six=1/4*5/6
so by bayes theorem=3/4*1/6 div by 1/4*5/6+3/4*1/6=3/8
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Solve the subsequent IVP. y′′ + 11y′ + 24 y = 0 y (0) =0 y′ (0)=-7 Solution The characteristic equation is as r 2 +11r + 24 = 0 ( r + 8) ( r + 3) = 0
what is dot
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assignment of mathematics in b.sc. 1sem
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