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A man is known to speak truth 3 out of 4 times.He throws adie and reports it is a six. Find the probability that it is actually a six.
Solution) we can get a six if a man says truth =3/4*1/6
or when he lies and it is not a six=1/4*5/6
so by bayes theorem=3/4*1/6 div by 1/4*5/6+3/4*1/6=3/8
The equation ax2 + 2hxy + by2 =0 represents a pair of straight lines passing through the origin and its angle is tan q = ±2root under h2-ab/(a+b) and even the eqn ax2+2hxy+by2+2gx+
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1.A=the set of whole numbers less tan 4 ? 2.B=the set of prime numbers less than 19 ? 3.C=the set of first three days of week?
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