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A man is known to speak truth 3 out of 4 times.He throws adie and reports it is a six. Find the probability that it is actually a six.
Solution) we can get a six if a man says truth =3/4*1/6
or when he lies and it is not a six=1/4*5/6
so by bayes theorem=3/4*1/6 div by 1/4*5/6+3/4*1/6=3/8
7(y + 3) - 2(x + 2) = 14, 4 (y - 2) + 3(x - 3) = 2 Ans: 7(y + 3) - 2 (x+ 2) = 14 --------- (1) 4(y- 2) + 3(x - 3) = 2 ----------(2) From (1) 7y +21 -
i dont get these questions they are hard for me
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Express the GCD of 48 and 18 as a linear combination. (Ans: Not unique) A=bq+r, where o ≤ r 48=18x2+12 18=12x1+6 12=6x2+0 ∴ HCF (18,48) = 6 now 6
history about cauchy mean value theorem ..
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