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The probability that a leap year will have 53 sunday is ? and how please explain it ?(a)1/7 (b) 2/7 (c) 5/7 (d)6/7Sol)A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days. The remaining 2 days may be any of the following : (i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday (iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday. n(S) = 7 n(E) = 2 P(E) = n(E) / n(S) = 2 / 7
Using the example provided below, if the measure ∠AEB = 5x + 40 and ∠BEC = x + 20, determine m∠DEC. a. 40° b. 25° c. 140° d. 65° c. The addition of the measurem
Mr. And Mrs. samuel visited Florida and purchased 120 oranges. They gave 1/4 of them to relatives, ate 1/12 of them in the hotel, and gave 1/3 of them to friends. The shipped the
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Example of Fractional Equations: Example: Solve the fractional equation (3x +8)/x +5 =0 Solution: Multiply both sides of the equation by the LCD (x). (x) ((3x
Reduction -when the original amount and the balance or remainder are known, to find the part that has been given away. (e.g., there were 15 toffees in a container, and there are
When three quantities a, b and c are in G.P., then the geometric mean "b" is calculated as follows. Since these quantities are in G.P., the r
if one side of a square is increased 4 inches and an adjacement side is multiplied by 4, the perimeter of the resulting rectangle is 3 times the perimeter of the square. find the s
One method of calculating the height of an object is to place a mirror on the ground and then position yourself so that the top of the object will be seen in the mirror. How high i
Unit circle: The unit circle is one of the most valuable tools to come out in trig. Unluckily, most people don't study it as well. Below is the unit circle with just the first
Now we start solving constant linear, coefficient and second order differential and homogeneous equations. Thus, let's recap how we do this from the previous section. We start alon
A non - leap year contains 365 days 52 weeks and 1 day more.i) We get 53 Sundays when the remaining day is Sunday.Number of days in week = 7∴ n(S) = 7Number of ways getting 53 Sundays.n(E) = 1n E 1n S 7=∴ Probability of getting 53 Sundays =1/7
A leap year consits of 366 days in those 364 days are completely 52 weeks so it contains 52 sundays remaining 2 days there are 2/7 probabilities are there.
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