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The probability that a leap year will have 53 sunday is ? and how please explain it ?(a)1/7 (b) 2/7 (c) 5/7 (d)6/7Sol)A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days. The remaining 2 days may be any of the following : (i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday (iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday. n(S) = 7 n(E) = 2 P(E) = n(E) / n(S) = 2 / 7
tens digit of a 2-digit number is twice its unit digit. If the sum of the digit is 12, find the number.
Determine the equation of the plane that consists of the points P = (1, -2, 0), Q = (3, 1, 4) and R = (0, -1, 2). Solution To write down the equation of plane there is a re
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the cost of paint used in a redecorating job is $65.70 .This is a reduction from its original cost of $82.13 .What is the percent decrease in the cost of paint to the nearest perce
find the amplitude and period of y=3 sin 2 pi x
i just have one question i need help on for my geometry homework
Prove that if f and g are functions, then f intersect g is a function by showing f intersect g = glA A={x:g(x)=f(x)}
Utilizes the second derivative test to classify the critical points of the function, h ( x ) = 3x 5 - 5x 3 + 3 Solution T
A non - leap year contains 365 days 52 weeks and 1 day more.i) We get 53 Sundays when the remaining day is Sunday.Number of days in week = 7∴ n(S) = 7Number of ways getting 53 Sundays.n(E) = 1n E 1n S 7=∴ Probability of getting 53 Sundays =1/7
A leap year consits of 366 days in those 364 days are completely 52 weeks so it contains 52 sundays remaining 2 days there are 2/7 probabilities are there.
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