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The probability that a leap year will have 53 sunday is ? and how please explain it ?(a)1/7 (b) 2/7 (c) 5/7 (d)6/7Sol)A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days. The remaining 2 days may be any of the following : (i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday (iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday. n(S) = 7 n(E) = 2 P(E) = n(E) / n(S) = 2 / 7
Write Triangles Named by the Lengths of Their Sides? An equilateral triangle is a triangle with three congruent sides. All three sides of this triangle are the same lengt
E1) Try and see the order in which different children fills numbers in the grid above. My claim is that all of them would fill in the ones, the fives and the tens first. Test my hy
-6x-4y=-6 x+2y=-3
Since we are going to be working almost exclusively along with systems of equations wherein the number of unknowns equals the number of equations we will confine our review to thes
Thorwarth M., Arisha, A. and Harper P., (2009) Simulation model to investigate flexible workload management for healthcare and servicescape environment, Proceedings of the 2009 Win
when i couulate the formula f 64 divided by 65 how do i do this
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I need to simple this rational expression, but I can''t figure out how. (x+1)/(x^2-2x-35)+(x^2+x-12)/(x^2-2x-24)(x^2-4x-12)/(x^2+2x-15)
A non - leap year contains 365 days 52 weeks and 1 day more.i) We get 53 Sundays when the remaining day is Sunday.Number of days in week = 7∴ n(S) = 7Number of ways getting 53 Sundays.n(E) = 1n E 1n S 7=∴ Probability of getting 53 Sundays =1/7
A leap year consits of 366 days in those 364 days are completely 52 weeks so it contains 52 sundays remaining 2 days there are 2/7 probabilities are there.
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