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The probability that a leap year will have 53 sunday is ? and how please explain it ?(a)1/7 (b) 2/7 (c) 5/7 (d)6/7Sol)A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days. The remaining 2 days may be any of the following : (i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday (iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday. n(S) = 7 n(E) = 2 P(E) = n(E) / n(S) = 2 / 7
Assume that i) Determine all the roots of f(x) = 0. ii) Determine the value of k that makes h continuous at x = 3. iii) Using the value of k found in (ii), sh
A bourbon that is 51 proof is 25.5% alcohol by volume while one that is 82 proof is 41% alcohol. How many liters of 51 proof bourbon must be mixed with 1.0 liter of 82 proof bourbo
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Example of Regression Equation An investment company advertised the sale of pieces of land at different prices. The given table shows the pieces of land their costs and acreag
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I don''t know how to do the next step like if I had 73 divided by 9 wouldn''t 7 go into nine 1 time then you have to do something else but that is the part I don''t understand
Q. Multiplying Mixed Numbers? Ans. Multiplying mixed numbers is a 3-step process: 1. Convert the mixed numbers to improper fractions 2. Multiply the fractions 3.
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Even and Odd Functions : This is the final topic that we have to discuss in this chapter. Firstly, an even function is any function which satisfies,
A non - leap year contains 365 days 52 weeks and 1 day more.i) We get 53 Sundays when the remaining day is Sunday.Number of days in week = 7∴ n(S) = 7Number of ways getting 53 Sundays.n(E) = 1n E 1n S 7=∴ Probability of getting 53 Sundays =1/7
A leap year consits of 366 days in those 364 days are completely 52 weeks so it contains 52 sundays remaining 2 days there are 2/7 probabilities are there.
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