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The probability that a leap year will have 53 sunday is ? and how please explain it ?(a)1/7 (b) 2/7 (c) 5/7 (d)6/7Sol)A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days. The remaining 2 days may be any of the following : (i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday (iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday. n(S) = 7 n(E) = 2 P(E) = n(E) / n(S) = 2 / 7
construct aquadrilaterl PQRSin which pq=3.5cm qr=6.5cm ,p=60 ,q=105 ,s=75
In her last gymnastics competition Keri scored a 5.6 on the floor exercise, 5.85 on the vault, and 5.90 on the balance beam. What was Keri's total score? Keri's three scores re
The production manager of Koulder Refrigerators must decide how many refrigerators to produce in each of the next four months to meet demand at the lowest overall cost. There is a
Evaluate following. (a) 625 3/4 Solution (a) 625 3/4 Again, let's employ both forms to calculate this one. 625 3/4 =( 625 1/4 ) 3 =(5) 3 = 12
If a telephone pole weighs 11.5 pounds per foot, how much does a 32-foot pole weigh? Multiply 11.5 by 32; 11.5 × 32 = 368 pounds.
WHAT TWO SIX DIDGIT NUMBERS CAN YOU ADD 984,357
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1. What is the probability that the two beverages will be of the same kind? 2. What is the probability that the two beverages will be different? 3. What is the probability
15(4*4*4*4*+5*5*5)+(13*13*13+3*3*3)
A non - leap year contains 365 days 52 weeks and 1 day more.i) We get 53 Sundays when the remaining day is Sunday.Number of days in week = 7∴ n(S) = 7Number of ways getting 53 Sundays.n(E) = 1n E 1n S 7=∴ Probability of getting 53 Sundays =1/7
A leap year consits of 366 days in those 364 days are completely 52 weeks so it contains 52 sundays remaining 2 days there are 2/7 probabilities are there.
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