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The probability that a leap year will have 53 sunday is ? and how please explain it ?(a)1/7 (b) 2/7 (c) 5/7 (d)6/7Sol)A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days. The remaining 2 days may be any of the following : (i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday (iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday. n(S) = 7 n(E) = 2 P(E) = n(E) / n(S) = 2 / 7
the median of a continuous frequency distribution is 21.if each observation is increased by 5. find the new median
Allan has been hired to mow the school soccer field that is 180 ft wide through 330 ft long. If his mower mows strips which are 2 feet huge, how many times must he mow across the w
Vectors This is a quite short section. We will be taking a concise look at vectors and a few of their properties. We will require some of this material in the other section a
a medical clinic performs three types of medical tests that use the same machines. Tests A, B,and C take 15 minutes, 30 minutes and 1 hours respectively, with respective profits of
Here we will use the expansion method Firstly lim x-0 log a (1+x)/x firstly using log property we get: lim x-0 log a (1+x)-logx then we change the base of log i.e lim x-0 {l
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Determine the centralizer and the order of the conjugacy: 1) Determine the centralizer and the order of the conjugacy class of the matrix [1, 1; 0, 1] in Gl 2 (F 3 ).
A professor is interested in decisive if attending college influences the level at which an individual cooperates with the police. The professor is not sure if attending college w
simplify the following: 3^5/2-3^1/2
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A non - leap year contains 365 days 52 weeks and 1 day more.i) We get 53 Sundays when the remaining day is Sunday.Number of days in week = 7∴ n(S) = 7Number of ways getting 53 Sundays.n(E) = 1n E 1n S 7=∴ Probability of getting 53 Sundays =1/7
A leap year consits of 366 days in those 364 days are completely 52 weeks so it contains 52 sundays remaining 2 days there are 2/7 probabilities are there.
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