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The probability that a leap year will have 53 sunday is ? and how please explain it ?(a)1/7 (b) 2/7 (c) 5/7 (d)6/7Sol)A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days. The remaining 2 days may be any of the following : (i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday (iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday. n(S) = 7 n(E) = 2 P(E) = n(E) / n(S) = 2 / 7
log4 (2x+4)-3=log4 3
Sherman took his pulse for 10 seconds and counted 11 beats. What is Sherman's pulse rate in beats per minute? A 10 second count is 1/6 of a minute. To find out the number of be
Q. How to Subtract fractions with the same denominators? Ans. Subtracting fractions is basically the same as adding them. If you don't know how to add fractions, you shoul
Joe walked 2 1/2 miles to school, 1/3 mile to work, and 1 1/4 miles to his friend's house. How several miles did Joe walk altogether? To find out the total distance walked, add
Grouping - situations in which we need to find the number of portions of a given size which can be obtained from a given quantity. (e.g., if there are 50 children in a class and t
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What are the marketing communications for Special K
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the circumference of a circle C of radius r is given by C=2pR.taking p to be 22/7 a)find the circumference when the radius is 28 cm b)find the radius when the circumference is 484
the sides of a quad taken at random are x+3y-7=0 x-2y-5=0 3x+2y-7=0 7x-y+17=0 obtain the equation of the diagonals
A non - leap year contains 365 days 52 weeks and 1 day more.i) We get 53 Sundays when the remaining day is Sunday.Number of days in week = 7∴ n(S) = 7Number of ways getting 53 Sundays.n(E) = 1n E 1n S 7=∴ Probability of getting 53 Sundays =1/7
A leap year consits of 366 days in those 364 days are completely 52 weeks so it contains 52 sundays remaining 2 days there are 2/7 probabilities are there.
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