Probability, Mathematics

Assignment Help:

The probability that a leap year will have 53 sunday is ? and how please explain it ?

(a)1/7    (b) 2/7    (c) 5/7    (d)6/7

Sol)
A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days. The remaining 2 days may be any of the following : (i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday (iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday. n(S) = 7 n(E) = 2 P(E) = n(E) / n(S) = 2 / 7


Related Discussions:- Probability

Divergence test - sequences and series, Divergence Test Once again...

Divergence Test Once again, do NOT misuse this test.  This test only says that a series is definite to diverge if the series terms do not go to zero in the limit.  If the

Given x+1/x=2cosy then find x^n +1/x^n, Here we know x can only be 1 or -1...

Here we know x can only be 1 or -1. so if it is 1 ans is 2. if x is -1, for n even ans will be 2 if x is -1 and n is odd ans will ne -2. so we can see evenfor negative x also an

Management, Discuss demanding total market demand verus gaing market share

Discuss demanding total market demand verus gaing market share

3/8:5/9, how do I change this ratio to a fraction

how do I change this ratio to a fraction

Shares and dividends, How do I proceed with a project on Shares and Dividen...

How do I proceed with a project on Shares and Dividends?

#title.automotive cruise control system., What are some of the interestingm...

What are some of the interestingmodern developments in cruise control systems that contrast with comparatively basic old systems

Percent of a number, Pay $40 for plan offered for $30 for plan what percent...

Pay $40 for plan offered for $30 for plan what percentage of savings

3/8/2013 5:50:18 AM

A non - leap year contains 365 days 52 weeks and 1 day more.
i) We get 53 Sundays when the remaining day is Sunday.
Number of days in week = 7
∴ n(S) = 7
Number of ways getting 53 Sundays.
n(E) = 1
n E 1
n S 7
=
∴ Probability of getting 53 Sundays =1/7

3/8/2013 5:50:56 AM

A leap year consits  of 366 days in those 364 days are completely 52 weeks so it contains 52 sundays remaining 2 days there are 2/7 probabilities are there.

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd