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The probability that a leap year will have 53 sunday is ? and how please explain it ?(a)1/7 (b) 2/7 (c) 5/7 (d)6/7Sol)A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days. The remaining 2 days may be any of the following : (i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday (iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday. n(S) = 7 n(E) = 2 P(E) = n(E) / n(S) = 2 / 7
I should have an account balance for $50.96. You took out $50.96 for a product on 6/18 which was NOT downloaded or delivered as it not available in the time frame I needed it. I am
g/6-2+(9/9)
#a invests Rs 15000IN COMPANY PAYING 10%WHEN Rs100 SHARE IS SOLD AT A PREMIUM OF Rs 20 after a yearASOLD SHARES AT Rs80 EACHAND INVESTEDPROCEEDS IN Rs75SHARES SELLING AT Rs 100 WZI
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1.)3 3/8 divided by 4 7/8 plus 3 2.)4 1/2 minus 3/4 divided by 2 3/8
Evaluating a Function You evaluate a function by "plugging in a number". For example, to evaluate the function f(x) = 3x 2 + x -5 at x = 10, you plug in a 10 everywhere you
A non - leap year contains 365 days 52 weeks and 1 day more.i) We get 53 Sundays when the remaining day is Sunday.Number of days in week = 7∴ n(S) = 7Number of ways getting 53 Sundays.n(E) = 1n E 1n S 7=∴ Probability of getting 53 Sundays =1/7
A leap year consits of 366 days in those 364 days are completely 52 weeks so it contains 52 sundays remaining 2 days there are 2/7 probabilities are there.
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