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The probability that a leap year will have 53 sunday is ? and how please explain it ?(a)1/7 (b) 2/7 (c) 5/7 (d)6/7Sol)A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days. The remaining 2 days may be any of the following : (i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday (iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday. n(S) = 7 n(E) = 2 P(E) = n(E) / n(S) = 2 / 7
Determine the measure of the vertex angle of the isosceles triangle. a. 34° b. 16° c. 58° d. 112° d. Simply substitute x = 34 into the equation for the vertex angle,
determine the square of the following numbers ... a.8 b.13 c.17 and d.80
limit x-a/|x-a| equals x-a [a]a [b]0 [c]-a [d]none 0f these
how it will be ? = ? + Ø
Differentiate following. Solution : It requires the product rule & each derivative in the product rule will need a chain rule application as well. T ′ ( x ) =1/1+(2x) 2
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Find the center and radius of the circle whose equation is 3 x^2 - 8 x+ 3 y^2+ 4 y+ 2 = 0
Question: Find Inverse Laplace Transform of the following (a) F(s) = (s-1)/(2s 2 +8s+13) (b) F(s)= e -4s /(s 2 +1) + (1/s 3 )
Polynomials in two variables Let's take a look at polynomials in two variables. Polynomials in two variables are algebraic expressions containing terms in the form ax n y m
A non - leap year contains 365 days 52 weeks and 1 day more.i) We get 53 Sundays when the remaining day is Sunday.Number of days in week = 7∴ n(S) = 7Number of ways getting 53 Sundays.n(E) = 1n E 1n S 7=∴ Probability of getting 53 Sundays =1/7
A leap year consits of 366 days in those 364 days are completely 52 weeks so it contains 52 sundays remaining 2 days there are 2/7 probabilities are there.
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