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The probability that a leap year will have 53 sunday is ? and how please explain it ?(a)1/7 (b) 2/7 (c) 5/7 (d)6/7Sol)A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days. The remaining 2 days may be any of the following : (i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday (iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday. n(S) = 7 n(E) = 2 P(E) = n(E) / n(S) = 2 / 7
Peggy's town has an average temperature of 23° Fahrenheit in the winter. What is the average temperature on the Celsius scale? If the total amount for both is 80, after that th
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In a triangle ABC, D &E is a are points on AB & AC ,if the one side of a triangle is 4cm & another side is 5 cm find that the ar(triangleABC):ar(BCDE)
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Covariance The variance is a measure of the variability or dispersion in a variable or data set. A measure of the variability of one variable (or data set) in relatio
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Write a procedure to obtain the inverse of an n by n matrix usingGaussian elimination. (You cannot use A - 1 or any of the built-in packages like 'MatrixInverse'.) Output any a
In figure, O is the centre of the Circle .AP and AQ two tangents drawn to the circle. B is a point on the tangent QA and ∠ PAB = 125 ° , Find ∠ POQ. (Ans: 125 o ) An s:
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Evaluate following limits. (a) (b) Solution There in fact isn't a whole lot to this limit. In this case because there is only a 6 in the denominator we'l
A non - leap year contains 365 days 52 weeks and 1 day more.i) We get 53 Sundays when the remaining day is Sunday.Number of days in week = 7∴ n(S) = 7Number of ways getting 53 Sundays.n(E) = 1n E 1n S 7=∴ Probability of getting 53 Sundays =1/7
A leap year consits of 366 days in those 364 days are completely 52 weeks so it contains 52 sundays remaining 2 days there are 2/7 probabilities are there.
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