Probability, Mathematics

Assignment Help:

The probability that a leap year will have 53 sunday is ? and how please explain it ?

(a)1/7    (b) 2/7    (c) 5/7    (d)6/7

Sol)
A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days. The remaining 2 days may be any of the following : (i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday (iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday. n(S) = 7 n(E) = 2 P(E) = n(E) / n(S) = 2 / 7


Related Discussions:- Probability

Find out the volume of the solid method of disks , Find out the volume of t...

Find out the volume of the solid obtained by rotating the region bounded by y = x 2 - 4x + 5 , x = 1 , x = 4 , and the x-axis about the x-axis. Solution : The firstly thing t

What is the probability shane rolls a 5, Shane rolls a die numbered 1 by 6....

Shane rolls a die numbered 1 by 6. What is the probability Shane rolls a 5? From 2:15 P.M. to 4:15 P.M. is 2 hours. After that, from 4:15 P.M. to 4:45 P.M. is another half hour

Graph y = cos ( x ) - common graph, Graph y = cos (x) Solution: There ...

Graph y = cos (x) Solution: There actually isn't a whole lot to this one.  Given the graph for -4 ? ≤ x ≤ 4 ? . Note that we can put all values of x in cosine (that wo

Calculate the limit of f (-4), Let's take a look at one more example to ens...

Let's take a look at one more example to ensure that we've got all the ideas about limits down that we've looked at in the last couple of sections. Example: Given the below gr

Circles, how to find equations of circles when given equations of centres o...

how to find equations of circles when given equations of centres on which it lies?

Find extrema & relative extrema f ( x ) = x3 on [-2, Recognizes the absolut...

Recognizes the absolute extrema & relative extrema for the given function.                                                    f ( x ) = x 3      on        [-2, 2] Solution :

3/8/2013 5:50:18 AM

A non - leap year contains 365 days 52 weeks and 1 day more.
i) We get 53 Sundays when the remaining day is Sunday.
Number of days in week = 7
∴ n(S) = 7
Number of ways getting 53 Sundays.
n(E) = 1
n E 1
n S 7
=
∴ Probability of getting 53 Sundays =1/7

3/8/2013 5:50:56 AM

A leap year consits  of 366 days in those 364 days are completely 52 weeks so it contains 52 sundays remaining 2 days there are 2/7 probabilities are there.

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd