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The probability that a leap year will have 53 sunday is ? and how please explain it ?(a)1/7 (b) 2/7 (c) 5/7 (d)6/7Sol)A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days. The remaining 2 days may be any of the following : (i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday (iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday. n(S) = 7 n(E) = 2 P(E) = n(E) / n(S) = 2 / 7
Seth has a pet goldfish. When he got his goldfish , it was only 5 centimeters long . Now it has grown to be 92 millimeters long. How many millimeters has the goldfish grown since
INTRODUCTION : When a child of seven isn't able to solve the sum 23+9, what could the reasons be? When she is asked to subtract 9 from 16, why does she write 9 - 16 = 13 ?
find the area of the irregular shape 2cm 4cm 4cm 2cm 5cm 5cm
The Daily News reported that 54% of people surveyed said in which they would vote for Larry Salva for mayor. Based on the survey results, if 23,500 people vote in the election, how
what are eigen values
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Given f (x) = - x 2 + 6 x -11 determine each of the following. (a) f ( 2) (b) f ( -10) (c) f (t ) Solution (a) f ( 2) = - ( 2) 2 + 6(2) -11 = -3 (
Evaluate the log function: Calculate 3log 10 2. Solution: Rule 3. log (A n ) = nlog b A 3log 10 2 = log 10 (2 3 ) = log 10 8 = 0.903
i dont know how to do probobility iam so bad at it
A non - leap year contains 365 days 52 weeks and 1 day more.i) We get 53 Sundays when the remaining day is Sunday.Number of days in week = 7∴ n(S) = 7Number of ways getting 53 Sundays.n(E) = 1n E 1n S 7=∴ Probability of getting 53 Sundays =1/7
A leap year consits of 366 days in those 364 days are completely 52 weeks so it contains 52 sundays remaining 2 days there are 2/7 probabilities are there.
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