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The probability that a leap year will have 53 sunday is ? and how please explain it ?(a)1/7 (b) 2/7 (c) 5/7 (d)6/7Sol)A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days. The remaining 2 days may be any of the following : (i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday (iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday. n(S) = 7 n(E) = 2 P(E) = n(E) / n(S) = 2 / 7
Quotient Rule (f/g)' = (f'g - fg')/g 2 Here, we can do this by using the definition of the derivative or along with Logarithmic Definition. Proof Here we do the pr
i love math..but i am afraid to study it... i mean i ma afraid that it may leave me in clay...what can you suggest me?
if two lines in s plane never intersect then they are parallel
for all real numbers x, x 0
WHAT DIVISION MEANS : Ask any primary school teacher which areas in arithmetic the children find very difficult. Division will probably top her list. This is not surprising. If y
A printer which sells for $190 is on sale for 20% off. What is the sale price of the printer? The printer is 20% off. That means that it is 80% of its original price (100% - 2
Q. Describe the Laws of Sines? Ans. Up to now we have dealt exclusively with right triangles. The Law of Sines and the Law of Cosines are used to solve oblique triangles
what is the result if 816.537 is rounded to the nearest tenth
A drug has a decay rate of k = - ¼ ln(¾) / hr. How soon after an initial dose of 1600 mg will the drug reach its minimum therapeutic value of 900 mg in the body?
an insurance salesman sells policies to 5 men, all of identical age in good health. the probability that a man of this particular age will be alive 30 years hence is 2/3.Find the p
A non - leap year contains 365 days 52 weeks and 1 day more.i) We get 53 Sundays when the remaining day is Sunday.Number of days in week = 7∴ n(S) = 7Number of ways getting 53 Sundays.n(E) = 1n E 1n S 7=∴ Probability of getting 53 Sundays =1/7
A leap year consits of 366 days in those 364 days are completely 52 weeks so it contains 52 sundays remaining 2 days there are 2/7 probabilities are there.
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