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The probability that a leap year will have 53 sunday is ? and how please explain it ?(a)1/7 (b) 2/7 (c) 5/7 (d)6/7Sol)A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days. The remaining 2 days may be any of the following : (i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday (iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday. n(S) = 7 n(E) = 2 P(E) = n(E) / n(S) = 2 / 7
Pai is rational or irrational
1. Give some Class 4 children around you problems like 15 x 6 to do dentally. Interact with them to find out the different strategies they use for doing it, and note these down.
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Evaluate each of the following. (a) 25 1/2 (b) 32 1/5 Solution (a) 25 1/2 Thus, here is what we are asking in this problem. 2
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when i couulate the formula f 64 divided by 65 how do i do this
It is not the first time that we've looked this topic. We also considered linear independence and linear dependence back while we were looking at second order differential equation
A non - leap year contains 365 days 52 weeks and 1 day more.i) We get 53 Sundays when the remaining day is Sunday.Number of days in week = 7∴ n(S) = 7Number of ways getting 53 Sundays.n(E) = 1n E 1n S 7=∴ Probability of getting 53 Sundays =1/7
A leap year consits of 366 days in those 364 days are completely 52 weeks so it contains 52 sundays remaining 2 days there are 2/7 probabilities are there.
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