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The probability that a leap year will have 53 sunday is ? and how please explain it ?(a)1/7 (b) 2/7 (c) 5/7 (d)6/7Sol)A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days. The remaining 2 days may be any of the following : (i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday (iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday. n(S) = 7 n(E) = 2 P(E) = n(E) / n(S) = 2 / 7
A ride in a taxicab costs $1.25 for the first mile and $1.15 for each additional mile. Which of the following could be used to computed the total cost y of a ride which was x miles
The remainder when 5^99 is divided by 13 Ans) 8 is the remainder.
robin runs 5 kilometers around the campus in the same length of time as he can walk 3 kilometers from his house to school. If he runs 4 kilometers per hour faster than he walks, ho
A cylindrical hole with a radius of 4 inches is cut through a cube. The edge of the cube is 5 inches. Determine the volume of the hollowed solid in terms of π. a. 125 - 80π
how can you determine trasportation schedule that minimizes cost
Higher Order Derivatives : Let's begin this section with the given function. f ( x ) = 5x 3 - 3x 2 + 10 x - 5 By this point we have to be a
Determine dy & Δy if y = cos ( x 2 + 1) - x as x changes from x = 2 to x = 2.03 . Solution Firstly let's deetrmine actual the change in y, Δy . Δy = cos (( 2.03) 2
(a) Derive the Marshalian demand functions and the indirect utility function for the following utility function: u(x1, x2, x3) = x1 1/6 x2 1/6 x3 1/6 x1≥ 0, x2≥0,x3≥ 0
3. How are Indian customers visiting Shoppers’ Stop any different from customers of developed western countries? 4. How should Shoppers’ Stop develop its demand forecasts?
detail on identity function
A non - leap year contains 365 days 52 weeks and 1 day more.i) We get 53 Sundays when the remaining day is Sunday.Number of days in week = 7∴ n(S) = 7Number of ways getting 53 Sundays.n(E) = 1n E 1n S 7=∴ Probability of getting 53 Sundays =1/7
A leap year consits of 366 days in those 364 days are completely 52 weeks so it contains 52 sundays remaining 2 days there are 2/7 probabilities are there.
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