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The probability that a leap year will have 53 sunday is ? and how please explain it ?(a)1/7 (b) 2/7 (c) 5/7 (d)6/7Sol)A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days. The remaining 2 days may be any of the following : (i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday (iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday. n(S) = 7 n(E) = 2 P(E) = n(E) / n(S) = 2 / 7
p=0
How many arrangements can be made from the letters of the word " VENUS " such that the order of the vowels remains the same?
Ask queThe low temperature in Anchorage, Alaska today was -4°F. The low temperature in Los Angeles, California was 63°F. What is the difference in the two low temperatures?stion #M
0+50x1-60-60x0+10
The distribution of sample means is not always a normal distribution. Under what circumstances is the distribution of sample means not normal?
Find the are of the rectilinear.if it is the difference between to isosceles trapezoid whose corrsponding sides are parallel.
Example Given the graph of f(x), illustrated below, find out if f(x) is continuous at x = -2 , x = 0 , and x = 3 . Solution To give answer of the question for each
from 0->1: Int sqrt(1-x^2) Solution) I=∫sqrt(1-x 2 )dx = sqrt(1-x 2 )∫dx - ∫{(-2x)/2sqrt(1-x 2 )}∫dx ---->(INTEGRATION BY PARTS) = x√(1-x 2 ) - ∫-x 2 /√(1-x 2 ) Let
Joey has 30 pages to read for history class tonight. He decided in which he would take a break while he finished reading 70% of the pages assigned. How many pages must he read befo
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A non - leap year contains 365 days 52 weeks and 1 day more.i) We get 53 Sundays when the remaining day is Sunday.Number of days in week = 7∴ n(S) = 7Number of ways getting 53 Sundays.n(E) = 1n E 1n S 7=∴ Probability of getting 53 Sundays =1/7
A leap year consits of 366 days in those 364 days are completely 52 weeks so it contains 52 sundays remaining 2 days there are 2/7 probabilities are there.
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