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The probability that a leap year will have 53 sunday is ? and how please explain it ?(a)1/7 (b) 2/7 (c) 5/7 (d)6/7Sol)A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days. The remaining 2 days may be any of the following : (i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday (iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday. n(S) = 7 n(E) = 2 P(E) = n(E) / n(S) = 2 / 7
functions f&g on R to R such that f=\g but fog=gof
Example Given the graph of f(x), illustrated below, find out if f(x) is continuous at x = -2 , x = 0 , and x = 3 . Solution To give answer of the question for each
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A real estate agent makes a 1.5% commission on her sales. What is her commission if she sells a $359,000 house? Multiply $359,000 by the decimal equivalent of 1.5% (0.015) to ?
MAKING CONNECTIONS : you have read about what the ability to think mathematically involves. In this section we shall discuss ways of developing this ability in children. As yo
A={2,3,5,7,11} B={1,3,5,7,9} C={10,20,30,40,......100} D={8,16,24,32,40} E={W,O,R,K} F={Red,Blue,Green} G={March,May} H={Jose,John,Joshua,Javier} I={3,6,9,12,15}
Which of the subsequent terms does NOT describe the number 9? Nine is NOT prime since it has 3 factors; 1, 3, and 9. Prime numbers have only 2 factors.
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#What is an easy way to find the area of any figure
A non - leap year contains 365 days 52 weeks and 1 day more.i) We get 53 Sundays when the remaining day is Sunday.Number of days in week = 7∴ n(S) = 7Number of ways getting 53 Sundays.n(E) = 1n E 1n S 7=∴ Probability of getting 53 Sundays =1/7
A leap year consits of 366 days in those 364 days are completely 52 weeks so it contains 52 sundays remaining 2 days there are 2/7 probabilities are there.
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