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Post order traversal:
The children of node are visited before the node itself; the root is visited last. Each node is visited after its descendents are visited.
Algorithm for postorder traversal is following:
1. Traverse left sub-tree in post order
2. Traverse right sub-tree in post order
3. visit root node.
Determining the space occupied through files & directories in a file system need a postorder traversal as the space occupied through directory needs calculation of space needed by all files in the directory (children in tree structure)
Figure: Calculation of space occupied by a file system: A post order traversal
Since each of the nodes is traversed only once, the time complexity of post order traversal is T(n) = O(n), where n refer to number of nodes in the tree.
null(nil) = true // nil refer for empty tree null(fork(e, T, T'))= false // e : element , T and T are two sub tree leaf(fork(e, nil, nil)) = true leaf(
I =PR/12 Numbers of years .Interest rate up to 1yrs . 5.50 up to 5yrs . 6.50 More than 5 yrs . 6.75 design an algorithm based on the above information
#question.show that the following inequality is correct or incorrect. n!=O(n^n)
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