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Post order traversal:
The children of node are visited before the node itself; the root is visited last. Each node is visited after its descendents are visited.
Algorithm for postorder traversal is following:
1. Traverse left sub-tree in post order
2. Traverse right sub-tree in post order
3. visit root node.
Determining the space occupied through files & directories in a file system need a postorder traversal as the space occupied through directory needs calculation of space needed by all files in the directory (children in tree structure)
Figure: Calculation of space occupied by a file system: A post order traversal
Since each of the nodes is traversed only once, the time complexity of post order traversal is T(n) = O(n), where n refer to number of nodes in the tree.
Ans: A procedure to reverse the singly linked list: reverse(struct node **st) { struct node *p, *q, *r; p = *st; q = NULL; while(p != NULL) { r =q;
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