Polynomials - represented by using arrays, Data Structure & Algorithms

Assignment Help:

 

/* the program accepts two polynomials as a input & prints the resultant polynomial because of the addition of input polynomials*/

#include

void main()

{

int poly1[6][2],poly2[6][2],term1,term2,match,proceed,i,j;

printf("Enter the number of terms in first polynomial. They must be less than 6:\n");

scanf("%d",&term1);

printf("Enter the number of terms in the second polynomial. They must be less than 6:\n");

scanf("%d",&term2);

printf("Enter the exponent and coefficient of every term of the first polynomial:\n");

for(i=0;i

{scanf("%d %d",&poly1[i][0],&poly1[i][1]);

}

printf("Enter the exponent and coefficient of every term of the second polynomial:\n");

for(i=0;i

{scanf("%d %d",&poly2[i][0],&poly2[i][1]);

}

printf("The resulting polynomial because of the addition of the input two polynomials:\n");

for(i=0;i

{

match=0;

for(j=0;j

{ if (match==0)

if(poly1[i][1]==poly2[j][1])

{ printf("%d   %d\n",(poly1[i][0]+poly2[j][0]), poly1[i][1]);

match=1;

}

}

}

for(i=0;i

{

 proceed=1;

for(j=0;j

{  if(proceed==1) if(poly1[i][1]!=poly2[j][1]) proceed=1;

else

proceed=0;

}

if (proceed==1)

printf("%d %d\n",poly1[i][0],poly1[i][1]);

}

for(i=0;i

{  proceed=1;

for(j=0;j

{  if(proceed==1) if(poly2[i][1]!=poly1[j][1]) proceed=1;

else

proceed=0;

}

if (proceed==1)

printf("%d %d",poly2[i][0],poly2[i][1]);

}

}

Output:

Enter the number of terms in first polynomial. They must be less than 6: 5. Enter the number of terms in the second polynomial .They must be less than 6: 4. Enter the coefficient & exponent of each of term of the first polynomial:

1 2

2 4

3 6

1 8

5 7

Enter the coefficient & exponent of every term of the second polynomial:

5 2

6 9

3 6

5 7

The resultant polynomial because of the addition of the input two polynomials:

6 2

6 6

10 7

2 4

1 8

6 9

The program prompted initially for number of terms of the two polynomials. Then, this prompted for the entry of terms of the 2 polynomials one after another. At first, this adds the coefficients of the corresponding terms of both the polynomials whose exponents are the similar. Then, this prints the terms of the primary polynomial who does not contain corresponding terms in the second polynomial along with the same exponent. Lastly, it prints the terms of the second polynomial that does not contain corresponding terms in the first polynomial.


Related Discussions:- Polynomials - represented by using arrays

Array implementation of a circular queue, A circular queue can be implement...

A circular queue can be implemented through arrays or linked lists. Program 6 gives the array implementation of any circular queue. Program 6: Array implementation of any Circu

Darw a flowchart to inputs top speeds of 5000 cars, Write an algorithm in t...

Write an algorithm in the form of a flowchart that: inputs top speeds (in km/hr.) of 5000 cars Outputs fastest speed and the slowest speed Outputs average (mean) s

State in detail about the integer, State in detail about the Integer ...

State in detail about the Integer Carrier set of the Integer ADT is the set {..., -2, -1, 0, 1, 2, ...}, and  operations on these values are addition, multiplication, subtrac

Graph traversal schemes, Q. Explain various graph traversal schemes and wri...

Q. Explain various graph traversal schemes and write their advantages and disadvantages. A n s . Graph Traversal Scheme is explained below In many troubles we wish

Implementation of stack, Implementation of Stack :- Stacks can be execu...

Implementation of Stack :- Stacks can be executed in the 2 ways: a)  Arrays b)  Linked List

Array, extra key inserted at end of array is called

extra key inserted at end of array is called

Process of accessing data stored in a serial access memory, The process of ...

The process of accessing data stored in a serial access memory is same to manipulating data on a By using stack  method.

C++, #What is the pointer

#What is the pointer

Binary tree creation, Binary tree creation struct NODE { struct N...

Binary tree creation struct NODE { struct NODE *left; int value; struct NODE *right; }; create_tree( struct NODE *curr, struct NODE *new ) { if(new->val

Depth first search and breadth first search, Q. Illustrate the result of ru...

Q. Illustrate the result of running BFS and DFS on the directed graph given below using vertex 3 as source.  Show the status of the data structure used at each and every stage.

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd