Polynomial : f(x).f(1/x), Mathematics

Assignment Help:

A polynomial satisfies the following relation f(x).f(1/x)= f(x)+f(1/x). f(2) = 33. fIND f(3)

Ans) The required polynomial is x^5 +1.

This polynomial satisfies the condition stated above.

Therefore, f[3] = 244.


Related Discussions:- Polynomial : f(x).f(1/x)

Continuity requirement, Continuity requirement : Let's discuss the continu...

Continuity requirement : Let's discuss the continuity requirement a little. Nowhere in the above description did the continuity requirement clearly come into play.  We need that t

Algebra, Multiple response question.Zack puts a mug of water ni his microwa...

Multiple response question.Zack puts a mug of water ni his microwave oven. He knows that the final temperature of the water will be a function of the number of seconds he heats the

Permuation and combination, how many words can be formed from letters of wo...

how many words can be formed from letters of word daughter such that each word contain 2vowles and 3consonant

Explain histogramsin details, Explain Histogramsin details? Another way...

Explain Histogramsin details? Another way to display frequencies is by using a histogram. The following is an example of a histogram using the data from the previous example:

Area of a hyperbolic wedge, The unit circle will be parametrized by (cosw, ...

The unit circle will be parametrized by (cosw, sinw). Provide a point on it, the region cut out by circle, the x-axis, and the line from the origin to this point has covered area w

Change of base of logarithms, Change of base: The final topic that we have...

Change of base: The final topic that we have to look at in this section is the change of base formula for logarithms. The change of base formula is,

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd