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Consider the frictionless piston-cylinder set-up with a linear spring as is shown below. The cylinder has an internal cross-sectional area of AC = 0.1 m2. Distances y1 and y4 are 0.005 m and 0.6 m respectively. The mass of the piston is mp = 80 kg and the environmental pressure is P0 = 100 kPa. Assume g = 10 m/s2. Initially the set-up contains saturated liquid water at T1 = 30ºC. 950 kJ of heat (1Q5) is now added until the piston is finally forced onto the upper stops. In total, 60 kJ/kg of specific work (1w5) was done. The following states are of interest: State 1: Initial state as is shown State 2: Piston leaves the bottom stops State 3: Piston gets into contact with the spring State 4: Piston gets into contact with the upper stops, Pressure is 1 MPa. State 5: Final state. Calculate the following: a) P1 b) P2 c) y3 d) T5.
Parallelogram law of forces: The law of parallelogram is used to determine the resultant of two forces acting at the point of a rigid body in plane and is inclined to each o
STEP S FOR SOLVING PROBLEM FOR FINDING POWER: 1. Use formula stress (s) = force (Maximum Tension)/Area Where; Area = b.t that is, Tmax = σ.b.t 2. Unit mass (m) = r.b.t.
what is steam trap?
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law of static friction
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