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The aim of this question is to help you become familiar with phasor diagrams, and in particular to see how the diagram changes when one of the system parameters (in this case resistance) varies. The diagram (right) represents the approximate equivalent circuit of an induction motor (copper and mechanical losses are ignored, and the permeability of magnetic core is considered infinite), supplied from a constant- voltage source V of angular frequency ω. The power in the fictitious resistance R represents the power converted from electrical to mechanical form, and the value of R is a function of the speed of the motor. Sketch phasor diagrams showing the current and the voltages across R and L when a) R = 0; b) R = 0.1ωL; c) R = ωL; d) R = 10ωL. (Use the same scale for each diagram; calculate angles; and use a protractor or drawing package to produce a set of decent diagrams so that they can be compared easily.
1. You may find it useful to recall the geometrical property of a semi-circle shown in the sketch.
2. Find the value of R (in terms of ωL) that yields maximum power, and the corresponding power.
Q. Advantages of subscriber loops signalling? (i) Information can be exchange between processors much more faster than when channel associated signalling is used. (ii) As a
connect two given points A and B by a parabolic curve when OA=60mm,OB=80mm and angle AOB=110 degree
Bias circuit requirements: Signal requirements for Class A amplifiers The Q-point is placed thus the transistor stays in active mode (does not shift to operation in the s
the forward resisitance of a semi conductor diode is 10 ohm, two such diodes used in full wave rectifier subjectto a sinusoidal voltage wave form. given by v(t)=308 , sin(100 pi t)
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Q. The unit impulse response h(t) of a linear system is h(t) = 5e -t cos(2t - 30°). Determine H(s).
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Define addressing modes of 8085. a) Immediate addressing b) Register addressing c) Direct addressing d) Indirect addressing e) Implicit addressing
Assume that an abrupt Si p-n junction with area 10-4 cm2 has NA=10 17 /cm 3 and ND=10 17 /cm 3 is working at room temperature. It is given that μ n = 700 cm 2 /v-s, μ P =250 cm
Indirect Addressing In this addressing mo e also ne of the operands is the stored in the memory. The memory address of the operand is specified by the register pair.
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