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A train goin from delhi to jaipur stops at 7 intermediate stations. 5 persons enter the train during the journey with 5 difefrent tickets of same class . How mant different set of tickets they could had??Solution) This is the condition if they all board the train from Delhi, though if they can board the train from any station . so here is the solutionEvery person can have two choices 1) Boarding Station 2)Destinationif B.S= Delhi Des=1,2,3,4,5,6,7,Jaipur = 8 choicesif B.S.= 1 Des=2,3,4,5,6,7,Jaipur = 7 choicesif B.S.= 2 Des=3,4,5,6,7,Jaipur = 6 choices...therefore the total type of tickets that a person can have =8+7+6+5+4+3+2+1 = 36choicesLikewise all the fove people can have these choices (May be recurring) .Then the total choices may be 365Though if they have different tickets then the permutation possible are 36*35*34*33*32
Poisson Mathematical Properties 1. The expected or mean value = np = λ Whereas; n = Sample Size p = Probability of success 2. The variance = np = ? 3. Standard dev
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Vectors - The Basics Let us start this section off with a quick discussion on what is the use of vector. Vectors are utilized to present quantities that have both a magnitude
THE MULTIPLICATION ALGORITHM : Some Class 3 children in a nearby school had been taught the standard multiplication. Algorithm, and had even done reasonably well in the tests bas
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Fermat's Theorem If f(x) has a relative extrema at x = c and f′(c) exists then x = c is a critical point of f(x). Actually, this will be a critical point that f′(c) =0.
From the top of a 200 m lighthouse, the angle of depression to a ship in the ocean is 23 . How far is the ship form the base of the lighthouse?
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