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A train goin from delhi to jaipur stops at 7 intermediate stations. 5 persons enter the train during the journey with 5 difefrent tickets of same class . How mant different set of tickets they could had??Solution) This is the condition if they all board the train from Delhi, though if they can board the train from any station . so here is the solutionEvery person can have two choices 1) Boarding Station 2)Destinationif B.S= Delhi Des=1,2,3,4,5,6,7,Jaipur = 8 choicesif B.S.= 1 Des=2,3,4,5,6,7,Jaipur = 7 choicesif B.S.= 2 Des=3,4,5,6,7,Jaipur = 6 choices...therefore the total type of tickets that a person can have =8+7+6+5+4+3+2+1 = 36choicesLikewise all the fove people can have these choices (May be recurring) .Then the total choices may be 365Though if they have different tickets then the permutation possible are 36*35*34*33*32
Question: Find all third order partial derivatives for the function F(x,y)= log xy+ e (x+y) -x/y.
jamal works every morning in his garden. yesterday he worked 3 AND 3-4HOURS. HE SPENT 1-3 OF THE TIME PULLING WEEDS. HOW MANY HOURS DID JAMAL SPEND PULLING WEEDS?
Evaluate following. ∫ 0 ln (1 + π ) e x cos(1-e x )dx Solution The limits are little unusual in this case, however that will happen sometimes therefore don't get
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how should i make my project on these topic?
Lucy's youth group increased $1,569 for charity. They decided to split the money evenly between 3 charities. How much will each charity receive? Divide the money raised through
We know that a factor is a quantity which divides the given quantity without leaving any remainder. Similar to LCM above we can find a highest common factor (HCF)
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