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A train goin from delhi to jaipur stops at 7 intermediate stations. 5 persons enter the train during the journey with 5 difefrent tickets of same class . How mant different set of tickets they could had??Solution) This is the condition if they all board the train from Delhi, though if they can board the train from any station . so here is the solutionEvery person can have two choices 1) Boarding Station 2)Destinationif B.S= Delhi Des=1,2,3,4,5,6,7,Jaipur = 8 choicesif B.S.= 1 Des=2,3,4,5,6,7,Jaipur = 7 choicesif B.S.= 2 Des=3,4,5,6,7,Jaipur = 6 choices...therefore the total type of tickets that a person can have =8+7+6+5+4+3+2+1 = 36choicesLikewise all the fove people can have these choices (May be recurring) .Then the total choices may be 365Though if they have different tickets then the permutation possible are 36*35*34*33*32
how can solve limits
Marks obtained by 70 students are given below: M arks 20 70 50 60 75 90 40 No.
Q. Illustrate Field Properties of Numbers? Ans. What the associative law of addition states is this: for any numbers a, b, and c,
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Consider the given graph G below. Find δ( G )=_____ , λ( G )= _____ , κ( G )= _____, number of edge-disjoint AF -paths=_____ , and number of vertex-disjoint AF -paths= ______
Year 1 2 3 4 5 6 7 8 9 10 Corn revenue 40 44 46
log6+log-4
how do you slove 4u-5=2u-13
Standard form of a complex number So, let's start out with some of the basic definitions & terminology for complex numbers. The standard form of a complex number is
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