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A train goin from delhi to jaipur stops at 7 intermediate stations. 5 persons enter the train during the journey with 5 difefrent tickets of same class . How mant different set of tickets they could had??Solution) This is the condition if they all board the train from Delhi, though if they can board the train from any station . so here is the solutionEvery person can have two choices 1) Boarding Station 2)Destinationif B.S= Delhi Des=1,2,3,4,5,6,7,Jaipur = 8 choicesif B.S.= 1 Des=2,3,4,5,6,7,Jaipur = 7 choicesif B.S.= 2 Des=3,4,5,6,7,Jaipur = 6 choices...therefore the total type of tickets that a person can have =8+7+6+5+4+3+2+1 = 36choicesLikewise all the fove people can have these choices (May be recurring) .Then the total choices may be 365Though if they have different tickets then the permutation possible are 36*35*34*33*32
write and solve a problem of multiplacation that uses: estimate explaning numbers picturs and another operation?
Dividing Whole Numbers: Example: Divide 347 by 5. Solution: Beginning from the left of the dividend, the divisor is divided into the
The following table contains some information about the model used. Assume the probabilities given by the model are those of being a good writer. Variable
y=2x+3=
Chain Rule : We've seen many derivatives. However, they have all been functions similar to the following kinds of functions. R ( z ) = √z f (t ) = t 50
Scalar Multiplication - Vector arithmetic Another arithmetic operation that we wish to look at is scalar multiplication. Specified the vector a → = (a 1 , a 2 , a 3 ) and any
I need help with one logarithm problem
2*8
finite or infinite 1]A={4,5,6,....}
solutions
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