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A train goin from delhi to jaipur stops at 7 intermediate stations. 5 persons enter the train during the journey with 5 difefrent tickets of same class . How mant different set of tickets they could had??Solution) This is the condition if they all board the train from Delhi, though if they can board the train from any station . so here is the solutionEvery person can have two choices 1) Boarding Station 2)Destinationif B.S= Delhi Des=1,2,3,4,5,6,7,Jaipur = 8 choicesif B.S.= 1 Des=2,3,4,5,6,7,Jaipur = 7 choicesif B.S.= 2 Des=3,4,5,6,7,Jaipur = 6 choices...therefore the total type of tickets that a person can have =8+7+6+5+4+3+2+1 = 36choicesLikewise all the fove people can have these choices (May be recurring) .Then the total choices may be 365Though if they have different tickets then the permutation possible are 36*35*34*33*32
Submit your working in (neat) handwritten form (do not type up your solutions). For the plots that you generate in Maple or Matlab, you can print them out and attach them at the en
Assume that i) Determine all the roots of f(x) = 0. ii) Determine the value of k that makes h continuous at x = 3. iii) Using the value of k found in (ii), sh
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1/sec A+tan A =1-sin A /cos A
Strategy for Series Now that we have got all of our tests out of the way it's time to think regarding to the organizing all of them into a general set of strategy to help us
the equation of a line that passes through (-3,4) and is perpendicular to the line y= -3x + 1 Also Graph the inequality: -3x + y And Use -4.9t(4.9t) + 10t + 1.5 to create a fu
I need help with direct variation between x and y
whats 2*2
What is Markov Chains or Processes?
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