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A train goin from delhi to jaipur stops at 7 intermediate stations. 5 persons enter the train during the journey with 5 difefrent tickets of same class . How mant different set of tickets they could had??Solution) This is the condition if they all board the train from Delhi, though if they can board the train from any station . so here is the solutionEvery person can have two choices 1) Boarding Station 2)Destinationif B.S= Delhi Des=1,2,3,4,5,6,7,Jaipur = 8 choicesif B.S.= 1 Des=2,3,4,5,6,7,Jaipur = 7 choicesif B.S.= 2 Des=3,4,5,6,7,Jaipur = 6 choices...therefore the total type of tickets that a person can have =8+7+6+5+4+3+2+1 = 36choicesLikewise all the fove people can have these choices (May be recurring) .Then the total choices may be 365Though if they have different tickets then the permutation possible are 36*35*34*33*32
Find the sum og series 1+(1+3)+(1+3+5)+.......+(1+3+...+15+17)=
1. Give some Class 4 children around you problems like 15 x 6 to do dentally. Interact with them to find out the different strategies they use for doing it, and note these down.
AUXILIARY METHODS There are other reprographic methods which although commonly used earlier, are now mainly used for specific purposes. We think you should be aware of these me
For the given function recognize the intervals where the function is increasing and decreasing and the intervals where the function is concave up & concave down. Utilizes this info
#question.areas of applications of linear program mes to solution to engineering problems.
An aeroplane is flying at a specific height of 5 km, and at a velocity of 450 km/hr. A camera on the ground is pointed towards the plane, at an angle θ from the horizontal. As the
If angle between asymtotes of hyperbola x^2/a^2-y^2/b^=1 is 120 degrees and product of perpendicular drawn from foci upon its any tangent is 9. Then find the locus of point of inte
can you explain it to me please
Consider the following multiplication in decimal notations: (999).(abc)=def132 ,determine the digits a,b,c,d,e,f. solution) a=8 b=6 c=8 d=8 e=6 f=7 In other words, 999 * 877 = 8
Special Forms There are a number of nice special forms of some polynomials which can make factoring easier for us on occasion. Following are the special forms. a 2 + 2ab +
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