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A train goin from delhi to jaipur stops at 7 intermediate stations. 5 persons enter the train during the journey with 5 difefrent tickets of same class . How mant different set of tickets they could had??Solution) This is the condition if they all board the train from Delhi, though if they can board the train from any station . so here is the solutionEvery person can have two choices 1) Boarding Station 2)Destinationif B.S= Delhi Des=1,2,3,4,5,6,7,Jaipur = 8 choicesif B.S.= 1 Des=2,3,4,5,6,7,Jaipur = 7 choicesif B.S.= 2 Des=3,4,5,6,7,Jaipur = 6 choices...therefore the total type of tickets that a person can have =8+7+6+5+4+3+2+1 = 36choicesLikewise all the fove people can have these choices (May be recurring) .Then the total choices may be 365Though if they have different tickets then the permutation possible are 36*35*34*33*32
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An educator placed 10 pebbles in a row and asked four-year-old Jaswant to count how many there were. She asked him to touch the pebbles .while counting them. Jaswant counted the pe
how to explain this strategy? how to do this strategy in solving a problem? can you give some example on how to solve this kind of strategy.
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Twice a number increased by 11 is equal to 32 less than three times the number. Find out the number. Let x = the number. Now translate every part of the sentence. Twice a numb
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solution of properties of definite integral
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