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If the charges are situated in a medium of permittivity ε, then the magnitude of the force between them will be, If the charges are situated in a medium of permittivity ε, then the magnitude of the force between them will be,
Fm = 1/4∏€ X q1q2/r2 -------------------------------------(2)
Dividing equations 1 and 2 we get F/Fm = € / €0 = € r. This ratio is called as relative permittivity or dielectric constant. This is equal to 1 in air. Hence the force between two charges depends on the medium in which they are situated.
A coil of 600 turns is wound uniformly on a ring of non-magnetic material. The ring has a uniform cross-sectional area of 200mm 2 and a mean circumference of 500mm. If the current
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comparison of magnetic moments using an vibrational magnetometer
It contains 35%- 90% nickels. Higher is the nickel content higher is the permeability and lower is the magnetic saturation of the alloy. MN, CO, and Mo can also be added in trace q
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