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Materials with 'hard' magnetic B/H characteristics often show a strong residual magnetism. This makes them suitable for making permanent magnets. If the ring material were magnetised, then the magnetised material itself will create a flux in the ring. No current carrying coil will be required.
For a permanent magnet, flux is produced by the alignment of magnetised domains within the material itself. (c.f earlier notes relating to residual magnetism in B/H curve). In this case, the flux exists without the need for a coil, i.e. N.I = 0. Hence applying Ampere's Law results in:
Hence eqn 1 and the B/H curve must be simultaneously satisfied and to give the flux density and magnetic field strength in the magnetic material (and hence also the air gap)
from equation (1) Bc/Hc=-Lc/Lgµ0
which is slope of a straight line. The flux density and magnetic field in the magnetic circuit is given by the point at which eqn (1) cuts the B/H curve. Permanent magnets are widely used in transducers:- loud speakers, measuring meters, D.C. motors etc.
I WANT TO KNOW WHAT IS THE THORY OF PLOTTING V-I CHARACTERISTIC CURVE OF SILICON DIODE ???
Zero Flag Since results is non zero in this example zero flag is reset.
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