Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
PC Bus and Interrupt System
The PC Bus utilized a bus controller, address latches, and data transceivers (bidirectional data buffers).
1) Bus controller :( Intel 8288 Bus Controller) coordinates activities on bus. It converts clock signal and CPU status into bus control signals. These control signals direct operations of data transceivers, latches and the I/O bus
2) Address latches: these are buffers for the address lines. They consider 2 reasons, fill the speed gap between the CPU and other devices; and permit the CPU pins to be utilized for other purposes.
3) Data transceivers: it is bidirectional data buffers
Interrupt processing: interrupt processing follows the below steps:
Once the external device recognizes the acknowledge, then it places the interrupt vector number on the data bus (through interrupt controller, in the case of IBM PC)
After the CPU receives the interrupt vector, it start the standard interrupt-initiation sequence: forming the interrupt vector address; then it is starting execution of the interrupt handler routine.
The main objective of the assignment is to explore the knowledge regarding parallel ports of a computer system. You can read and write datato/from the parallel port using IN and OU
#questioexamplesn..
using 8086 assembly language that interchange upper four bits to lower four bits. assume that data store in byte memory and it written back to same location. and assume the data as
.MODEL SMALL .STACK 100H .DATA PROMPT DB \''The 256 ASCII Characters are : $\'' .CODE MAIN PROC MOV AX, @DATA ; initialize DS MOV DS, AX
Interrupt System Based on Single 8259 A The 8259A is contained in a 28-pin dual-in-line package that need only a + 5-V supply voltage. Its organization is shown in given figur
move a byte string ,16 bytes long from the offset 0200H to 0300H in the segment 7000H..
Declare 1 constant. This can be done just below the prototype section. Put the following divider above the constant section. ;************************ Constants ****************
programs
Write a program to solve problem 9, Summation Program, on page 179 of chapter 5 in the textbook (book:kip Irvine Assembly Language sixth edition)
hey ,, I need to know how to let a symbol moves with mouse ??
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd