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PC Bus and Interrupt System
The PC Bus utilized a bus controller, address latches, and data transceivers (bidirectional data buffers).
1) Bus controller :( Intel 8288 Bus Controller) coordinates activities on bus. It converts clock signal and CPU status into bus control signals. These control signals direct operations of data transceivers, latches and the I/O bus
2) Address latches: these are buffers for the address lines. They consider 2 reasons, fill the speed gap between the CPU and other devices; and permit the CPU pins to be utilized for other purposes.
3) Data transceivers: it is bidirectional data buffers
Interrupt processing: interrupt processing follows the below steps:
Once the external device recognizes the acknowledge, then it places the interrupt vector number on the data bus (through interrupt controller, in the case of IBM PC)
After the CPU receives the interrupt vector, it start the standard interrupt-initiation sequence: forming the interrupt vector address; then it is starting execution of the interrupt handler routine.
ROR : Rotate Right without Carry: This instruction rotates the contents of destination operand to the bit-wise right either by one or by the count specified in register CL, exclud
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INTO : Interrupt on Overflow:- It is executed, when the overflow flag OF is set. The new contents of IP and CS register are taken from the address 0000:0000 as described in INT
INC: Increment : - This instruction increments the contents of the particular memory or register location by the value 1. All the condition code flags are affected except the carry
RCR: Rotate Right through Carry:- This instruction rotates the contents bit-wise of the destination operand right by the specified count through carry flag (CF). For each operati
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MLIL: Unsigned Multiplication Byte or Word: This instruction multiplies an unsigned byte or word by the contents of the AL. The unsigned byte or word can be in any one of the gene
Write a program to do the following: 1. Print your name 2. Using a bottom testing loop, prompt the user to enter a number from 1 to 5. If the number entered is not 1..5, pri
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