Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
PC Bus and Interrupt System
The PC Bus utilized a bus controller, address latches, and data transceivers (bidirectional data buffers).
1) Bus controller :( Intel 8288 Bus Controller) coordinates activities on bus. It converts clock signal and CPU status into bus control signals. These control signals direct operations of data transceivers, latches and the I/O bus
2) Address latches: these are buffers for the address lines. They consider 2 reasons, fill the speed gap between the CPU and other devices; and permit the CPU pins to be utilized for other purposes.
3) Data transceivers: it is bidirectional data buffers
Interrupt processing: interrupt processing follows the below steps:
Once the external device recognizes the acknowledge, then it places the interrupt vector number on the data bus (through interrupt controller, in the case of IBM PC)
After the CPU receives the interrupt vector, it start the standard interrupt-initiation sequence: forming the interrupt vector address; then it is starting execution of the interrupt handler routine.
General Data Registers Given figure indicate the register organization of 8086. The registers DX, CX, BX and AX are the general purpose 16-bit registers. AX is behaved as 16-bi
Assembler Directives and Operators The major advantage of machine language programming is directly that the memory control is in the hands of the programmer, so that, he can be
(1) Write a program that will: (a) display "Enter Your Name:" (b) convert the entered name to Capital letters (if small), If any other character is entered, the program wil
Displacement addressing technique
Write a MIPS/SPIM assembly language program that prints the smallest and largest values found in a non-empty table of N word-sized integers. The address of the first entry in your
Assume that the registers are initialized to EAX=12345h,EBX =9528h ECX=1275h,EDX=3001h sub AH,AH sub DH,DH mov DL,AL mov CL,3 shl DX,CL shl AX,1 add DX,AX
) What is the difference between re-locatable program and re-locatable data?
Example : Write a program to move the contents of the memory location 0500H to BX and also to register CX. Add immediate byte 05H to the data residing in memory location, whose ad
IRET : Return from ISR:- When an interrupt service routine is called, before transferring control to it, the IP, CS register and flag registers are stored in the stack to ment
how to store a bulk data in a external eeprom
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd