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PC Bus and Interrupt System
The PC Bus utilized a bus controller, address latches, and data transceivers (bidirectional data buffers).
1) Bus controller :( Intel 8288 Bus Controller) coordinates activities on bus. It converts clock signal and CPU status into bus control signals. These control signals direct operations of data transceivers, latches and the I/O bus
2) Address latches: these are buffers for the address lines. They consider 2 reasons, fill the speed gap between the CPU and other devices; and permit the CPU pins to be utilized for other purposes.
3) Data transceivers: it is bidirectional data buffers
Interrupt processing: interrupt processing follows the below steps:
Once the external device recognizes the acknowledge, then it places the interrupt vector number on the data bus (through interrupt controller, in the case of IBM PC)
After the CPU receives the interrupt vector, it start the standard interrupt-initiation sequence: forming the interrupt vector address; then it is starting execution of the interrupt handler routine.
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INTO : Interrupt on Overflow:- It is executed, when the overflow flag OF is set. The new contents of IP and CS register are taken from the address 0000:0000 as described in INT
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Interrupt System Based on Single 8259 A The 8259A is contained in a 28-pin dual-in-line package that need only a + 5-V supply voltage. Its organization is shown in given figur
Interrupt System Based on Multiple 8259As A multiple 8259A interrupt system is diagrammed in given figure in this figure data bus drivers are not indicated, but they could be i
Program : A program to move a string of the data words from offset 2000H to offset 3000H the length of the string is OFH. Solution : For writing this program, we will use
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8279 Keyword /Display Controller : Figure shows the structure of 8279 and its interface to the bus. Addressing is according to the table given below. CS RD
Assume that the registers are initialized to EAX=12345h,EBX =9528h ECX=1275h,EDX=3001h sub AH,AH sub DH,DH mov DL,AL mov CL,3 shl DX,CL shl AX,1 add DX,AX
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