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If y 1 (t) and y 2 (t) are two solutions to a linear, homogeneous differential equation thus it is y (t ) = c 1 y 1 (t ) + c 2 y 2 (t ) ........................(3) Remem
A boy standing on a horizontal plane finds a bird flying at a distance of 100m from him at an elevation of 300. A girl standing on the roof of 20 meter high building finds the angl
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Describe differance between Mean vs. Mode ? Every set of numbers or data has a mean and a mode value. The mean is the average value of all the numbers in the set. The mode is t
Determine the general solution to 2t 2 y'' + ty' - 3y = 0 It given that y (t) = t -1 is a solution. Solution Reduction of order needs that a solution already be iden
The subsequent type of first order differential equations which we'll be searching is correct differential equations. Before we find in the full details behind solving precise diff
Solve the subsequent IVP. cos(x) y' + sin(x) y = 2 cos 3 (x) sin(x) - 1 y(p/4) = 3√2, 0 Solution : Rewrite the differential equation to determine the coefficient of t
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If y 1 (t) and y 2 (t) are two solutions to y′′ + p (t ) y′ + q (t ) y = 0 So the Wronskian of the two solutions is, W(y 1 ,y 2 )(t) = =
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