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Parallel to the line specified by 10 y + 3x= -2
In this case the new line is to be parallel to the line given by 10 y ? 3x ? -2 and so it have to have the similar slope as this line. Thus we know that,
m 2 =- 3/10
Now, we've got a point on the new line, (8, 2) ,& we know the slope of the new line, - 3, so ,we can employ the point-slope form of the line to write down the equation of the new line. Following is the equation,
y= 2 - 3/10 ( x - 8)
= 2- 3/10x + 24/10
= - 3/10x +44/10
y = -(3/10)x+22/5
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In triangle ABC, cosecA(sinB.sinC+cosB.sinC) is equal to..?
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