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If roots of (x-p)(x-q) = c are a and b what will be the roots of (x-a)(x-b) = -c please explain? Ans) (x-p)(x-q)=c x2-(p+q)x-c=0 hence, a+b=p+q and a.b=pq-c
5+5
In the previous section we looked at the method of undetermined coefficients for getting a particular solution to p (t) y′′ + q (t) y′ + r (t) y = g (t) .....................
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