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Overloading Binary Operators
class SI
{float i,p,n,r,a;
public:
SI(){};
SI(int gp,int gn, int gr);
void putdata(void);
SI operator+(SI);
};
SI SI::operator+(SI i1)
{SI i2; i2.p=p+i1.p; i2.i=i+i1.i; i2.a=a+i1.a; return i2;
}
void SI::putdata(void)
{cout<<"Principle is: "< cout<<"Interest is "< cout<<"Amount is "< } SI::SI(int gp,int gn, int gr) {p=gp;n=gn;r=gr; i=(p*n*r)/100; a=p+i; } int main() { SI i1,i2,i3; i1=SI(1000,2,10); i1.putdata(); cout< return 0; }
cout<<"Interest is "< cout<<"Amount is "< } SI::SI(int gp,int gn, int gr) {p=gp;n=gn;r=gr; i=(p*n*r)/100; a=p+i; } int main() { SI i1,i2,i3; i1=SI(1000,2,10); i1.putdata(); cout< return 0; }
cout<<"Amount is "< } SI::SI(int gp,int gn, int gr) {p=gp;n=gn;r=gr; i=(p*n*r)/100; a=p+i; } int main() { SI i1,i2,i3; i1=SI(1000,2,10); i1.putdata(); cout< return 0; }
SI::SI(int gp,int gn, int gr)
{p=gp;n=gn;r=gr; i=(p*n*r)/100; a=p+i;
int main()
{ SI i1,i2,i3;
i1=SI(1000,2,10); i1.putdata(); cout< return 0; }
return 0;
Polymorphism C++ supports this idea - that different objects do "the right thing "- by function polymorphism and class polymorphism. Poly means many, while morph means form.
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Hi, Can i get a quote for my Programming assignment
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