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GALLIUM PHOSPIDE: It has band gap of 2.3ev. it can be used for light emitting diodes which can emit green or red light. The red light is obtained with zinc or cadmium oxide doping.
SELENIUM: It is found in crystalline and non-crystalline form. It is used as rectifier material for photo voltaic cells and for xerographic printing. Selenium films are used as photo electric light meters. Its melting point is 2200C.
LEAD: it is soft heavy and bluish gray metal. It is highly resistant to many chemical actions but can corrode by nitric acid, lime and rotten organic substances. Lead and its compounds are toxic. It is mechanically weak it cannot withstand vibrations at high temperatures. It alloys easily with Tin and zinc and forms many commercial alloys, including solders and bearing metals.
Mica is an inorganic mineral. It is one of the best natural insulating materials available. In spite of the tremendous progress made in insulation technology this material and its
find the dimensions of the following i.power ii.velocity iii.force
sonic waves
The cross-sectional areas of the pistons in the system shown below have a ratio of 25 to 1. If the maximum force that can be applied to the small piston is 12 N. What is the
definition and explanation
Verify the value and tolerance of a resistor having a colour coding of: blue-grey-orange- red Determine the value and tolerance of a resistor having a colour coding of: yellow-
How is sensitive flame method used for detection of ultrasonic waves? Sensitive flame method: A narrow sensitive flame is shifted along the medium. At the situations of anti
Question 1. Discuss the concept of longitudinal and transverse relation. 2. What is k-space? Write a note on k-space trajectories. 3. Name the 3 components of MRI system.
True or False 1)Clothes always get static cling when dried in a clothes dryer 2) Dust stick to all charged objects 3) Static Electricity always stays in one place and never move
Q. In the given circuit, calculate the potential differences across each resistor Solution : i) R s = R 1 + R 2 + R 3 = 10Ω ii) Current in circuit I = V/R s
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