Operations on b-trees, Data Structure & Algorithms

Assignment Help:

Operations on B-Trees

Given are various operations which can be performed on B-Trees:

  • Search
  • Create
  • Insert

B-Tree does effort to minimize disk access and the nodes are usually stored on disk

All the nodes are supposed to be stored into secondary storage instead of primary storage. All references to a given node are preceded through a read operation. Likewise, once a node is changed and it is no longer required, it has to be written out to secondary storage with write operation.

Given is the algorithm for searching a B-tree:

B-Tree Search (x, k)

i < - 1

while i < = n [x] and k > keyi[x]

do i ← i + 1

if i < = n [x] and k = key1 [x]

then return (x, i)

if leaf [x]

then return NIL

else Disk - Read (ci[x])

return B - Tree Search (Ci[x], k)

The search operation is alike to binary tree. Instead of selecting between a left and right child as in binary tree, a B-tree search have to make an n-way choice.

The right child is selected by performing a linear search of the values into the node. After determining the value greater than or equal to desired value, the child pointer to the instantaneous left to that value is followed.

The exact running time of search operation based upon the height of the tree. Given is the algorithm for the creation of a B-tree:

B-Tree Create (T)

x ← Allocate-Node ( )

 Leaf [x] ← True

n [x] ← 0

Disk-write (x)

root [T] ← x

 

The above denoted algorithm creates an empty B-tree through allocating a new root which has no keys and is a leaf node.

Given is the algorithm for insertion into a B-tree:

B-Tree Insert (T,K)

r ← root (T)

if n[r] = 2t - 1

then S ← Allocate-Node ( )

root[T] ← S

leaf [S] ← FALSE

n[S] ← 0

C1 ← r

B-Tree-Split-Child (s, I, r)

B-Tree-Insert-Non full (s, k)

else

B - Tree-Insert-Non full (r, k)

To carry on an insertion on B-tree, the proper node for the key has to be located. Next, the key has to be inserted into the node.

If the node is not full prior to the insertion, then no special action is needed.

If node is full, then the node has to be split to make room for the new key. As splitting the node results in moving one key to the parent node, the parent node ha not be full. Else, another split operation is required.

This procedure may repeat all the way up to the root and may need splitting the root node.


Related Discussions:- Operations on b-trees

Binary tree creation, Binary tree creation struct NODE { struct N...

Binary tree creation struct NODE { struct NODE *left; int value; struct NODE *right; }; create_tree( struct NODE *curr, struct NODE *new ) { if(new->val

Tree structure, We would like to implement a 2-4Tree containing distinct in...

We would like to implement a 2-4Tree containing distinct integer keys. This 2-4Tree is defined by the ArrayList Nodes of all the 2-4Nodes in the tree and the special 2-4Node Root w

Applications of avl trees, AVL trees are applied into the given situations:...

AVL trees are applied into the given situations: There are few insertion & deletion operations Short search time is required Input data is sorted or nearly sorted

Sorting, Sort the following array of elements using quick sort: 3, 1, 4, 1,...

Sort the following array of elements using quick sort: 3, 1, 4, 1, 5, 9, 2, 6, 5, 3, 5, 8.

Algorithm of decorated graph, As we talked in class, a program with two int...

As we talked in class, a program with two integer variables is universal. Now, we consider a special form of four variableprograms. Let G = (V; E) be a directed graph, where V is a

STACK, WHAT IS THE PURPOSE OF STACK IN C

WHAT IS THE PURPOSE OF STACK IN C

Programme in c to create a single linked list, Q. Write  down a   p...

Q. Write  down a   programme  in  C  to  create  a  single  linked  list also  write the functions to do the following operations (i)  To insert a new node at the end (ii

Circular queue, explain implementation of circular queue insert,delete oper...

explain implementation of circular queue insert,delete operations

Addressing modes, Compare zero-address, one-address, two-address, and three...

Compare zero-address, one-address, two-address, and three-address machines by writing programs to compute: Y = (A – B X C) / (D + E X F) for each of the four machines. The inst

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd