Operations on b-trees, Data Structure & Algorithms

Assignment Help:

Operations on B-Trees

Given are various operations which can be performed on B-Trees:

  • Search
  • Create
  • Insert

B-Tree does effort to minimize disk access and the nodes are usually stored on disk

All the nodes are supposed to be stored into secondary storage instead of primary storage. All references to a given node are preceded through a read operation. Likewise, once a node is changed and it is no longer required, it has to be written out to secondary storage with write operation.

Given is the algorithm for searching a B-tree:

B-Tree Search (x, k)

i < - 1

while i < = n [x] and k > keyi[x]

do i ← i + 1

if i < = n [x] and k = key1 [x]

then return (x, i)

if leaf [x]

then return NIL

else Disk - Read (ci[x])

return B - Tree Search (Ci[x], k)

The search operation is alike to binary tree. Instead of selecting between a left and right child as in binary tree, a B-tree search have to make an n-way choice.

The right child is selected by performing a linear search of the values into the node. After determining the value greater than or equal to desired value, the child pointer to the instantaneous left to that value is followed.

The exact running time of search operation based upon the height of the tree. Given is the algorithm for the creation of a B-tree:

B-Tree Create (T)

x ← Allocate-Node ( )

 Leaf [x] ← True

n [x] ← 0

Disk-write (x)

root [T] ← x

 

The above denoted algorithm creates an empty B-tree through allocating a new root which has no keys and is a leaf node.

Given is the algorithm for insertion into a B-tree:

B-Tree Insert (T,K)

r ← root (T)

if n[r] = 2t - 1

then S ← Allocate-Node ( )

root[T] ← S

leaf [S] ← FALSE

n[S] ← 0

C1 ← r

B-Tree-Split-Child (s, I, r)

B-Tree-Insert-Non full (s, k)

else

B - Tree-Insert-Non full (r, k)

To carry on an insertion on B-tree, the proper node for the key has to be located. Next, the key has to be inserted into the node.

If the node is not full prior to the insertion, then no special action is needed.

If node is full, then the node has to be split to make room for the new key. As splitting the node results in moving one key to the parent node, the parent node ha not be full. Else, another split operation is required.

This procedure may repeat all the way up to the root and may need splitting the root node.


Related Discussions:- Operations on b-trees

Compound interest, Write the algorithm for compound interest

Write the algorithm for compound interest

Explain merge sort, Merge sort: Merge sort is a sorting algorithm that ...

Merge sort: Merge sort is a sorting algorithm that uses the idea of split and conquers. This algorithm splits the array into two halves, sorts them separately and then merges t

A linear list of elements in which deletion can be done, A linear list of e...

A linear list of elements in which deletion can be done from one end (front) and insertion can take place only at the other end (rear) is called as a   Queue.

Determine about the push operation, Determine about the push operation ...

Determine about the push operation A Container may or may not be accessible by keys, so it can't make assumptions about element retrieval methods (for example, it cannot have a

Rules for abstract data type-tree, null(nil) = true                     // ...

null(nil) = true                     // nil refer for empty tree null(fork(e, T, T'))= false   //  e : element , T and T are two sub tree leaf(fork(e, nil, nil)) = true leaf(

Binary search tree in ascending order, In order to get the contents of a Bi...

In order to get the contents of a Binary search tree in ascending order, one has to traverse it in In-order

Travelling salesman problem, Example 3: Travelling Salesman problem G...

Example 3: Travelling Salesman problem Given: n associated cities and distances among them Find: tour of minimum length that visits all of city. Solutions: How several

Representation of a sparse matrix, Let us assume a sparse matrix from stora...

Let us assume a sparse matrix from storage view point. Assume that the entire sparse matrix is stored. Then, a significant amount of memory that stores the matrix consists of zeroe

Post order traversal, Post order traversal: The children of node are vi...

Post order traversal: The children of node are visited before the node itself; the root is visited last. Each node is visited after its descendents are visited. Algorithm fo

Circular queues and implement circular queues using array, Explain what are...

Explain what are circular queues? Write down routines required for inserting and deleting elements from a circular queue implemented using arrays.           Circular queue:

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd