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Illustrates that each of the following numbers are solutions to the following equation or inequality. (a) x = 3 in x 2 - 9 = 0 (b) y = 8 in 3( y + 1) = 4 y - 5 Solution
Let u = sin(x). Then du = cos(x) dx. So you can now antidifferentiate e^u du. This is e^u + C = e^sin(x) + C. Then substitute your range 0 to pi. e^sin (pi)-e^sin(0) =0-0 =0
Related Rates : In this section we will discussed for application of implicit differentiation. For these related rates problems usually it's best to just see some problems an
Simplify following. Suppose that x, y, & z are positive. √ y 7 Solution In this case the exponent (7) is larger than the index (2) and thus the fir
We have to enclose a field along with a fence. We contain 500 feet of fencing material & a building is on one side of the field & thus won't require any fencing. Find out the dime
what is 10+5..
Midpoint Rule - Approximating Definite Integrals This is the rule which should be somewhat well-known to you. We will divide the interval [a,b] into n subintervals of equal wid
The positive value of k for which x 2 +Kx +64 = 0 & x 2 - 8x + k = 0 will have real roots . Ans: x 2 + K x + 64 = 0 ⇒ b 2 -4ac > 0 K 2 - 256 > 0 K
Example of Imaginary Numbers: Example 1: Multiply √-2 and √-32 Solution: (√-2)( √-32) = (√2i)( √32i) =√64 (-1) =8 (-1) =-8 Example 2: Divid
Tori was asked to provide an example of the commutative property of addition. Which of the subsequent choices would be correct? Using the simple interest formula Interest = pr
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