Operating systems, Assembly Language

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Cache components-microprocessor, Cache components The cache sub-system ...

Cache components The cache sub-system may be divided into 3 functional blocks: Tag RAM, SRAM and theCache Controller. In real designs, these blocks can be implemented  by multi

Program to evaluate equation, Write a program to evaluate the following exp...

Write a program to evaluate the following expression. You are to evaluate the following equation: num1 - (input + num2) - (num3 + num4) Input will be a hex number input by

Register organization of 8086-microprocessor, Register Organization of 8086...

Register Organization of 8086 8086  has  a great  set  of registers  containing  special  purpose and general  purpose  registers.  All the 8086 resisters are 16-bit registers.

Motorola 68000 series, Motorola 68000 Series : 68000microprocessor is a...

Motorola 68000 Series : 68000microprocessor is a 16 bit processor that has addressing space of 65536 locations, each of which holds a 64-bits word; In order to address those lo

NASM assembly language programming, NASM assembly language program: Consid...

NASM assembly language program: Consider a sequence of 19 strictly positive decimal digits, most likely stored in an array. There are obviously duplicates, and the sequence is un

Boolean and comparison instructions, what will be the value of EAX after fo...

what will be the value of EAX after following instructions execute? mov bx, 0FFFFh and bx, 6Bh

Sbb-arithmetic instruction-microprocessor, SBB: Subtract  with Borrow  :- ...

SBB: Subtract  with Borrow  :- The subtract with borrow instruction subtracts the source operand and the borrow flag (CF) which might reflect the result of the past calculations,

Read file in 8086, Write a procedure to read a text file and copy its cont...

Write a procedure to read a text file and copy its contents to another text file using 8086 assembly language .

Microprocessor, from pin description it seems that 8086 has 16 address/data...

from pin description it seems that 8086 has 16 address/data lines i.e.AD0_AD15.The physical address is however is larger than 2^16.How this condition can be handled

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General Bus Operation The 8086 has a joined data and address bus commonly referred to as a time multiplexed address and data bus. The major reason behind  multiplexing address

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