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A function is called one-to-one if no two values of x produce the same y. It is a fairly simple definition of one-to-one although it takes an instance of a function which isn't one-to-one to illustrate just what it means. However Before doing that we have to note that this definition of one-to-one is not actually the mathematically correct definition of one-to-one. This is similar to the mathematically correct definition it just doesn't employ the entire notation from the formal definition.
Now, let's look at an example of a function which isn't one-to-one. The function f ( x )= x2 is not one-to-one since both f ( -2) = 4 and f ( 2) = 4 . In other terms there are two distinct values of x which produce the similar value of y. Note that we can turn f ( x ) = x2 into a one-to-one function if we limit ourselves to 0 ≤ x <∞ . Sometimes it can be done with functions.
Illustrating that a function is one-to-one is frequently a tedious and often difficult. For the most of the part we are going to suppose that the functions which we're going to be dealing along with in this section are one- to-one. We did have to talk regarding one-to-one functions though since only one-to-one functions can be inverse functions.
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If you sell a kayak for $400 and your sales per day averages $5200. Assume the sales per day is a linear function of price of kayak. write an equation describing the relationship.
resolve this a(x)=\/x-4+3
Example : determine the zeroes of following polynomials. P ( x)= 5x 5 - 20x 4 +5x3 + 50x2 - 20x - 40 = 5 (x + 1) 2 ( x - 2) 3 Solution In this the factoring has been
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Horizontal Shifts These are quite simple as well though there is one bit where we have to be careful. Given the graph of f ( x ) the graph of g ( x ) = f ( x + c ) will be t
larry has a propane tank in the shape of a cylinder with a hemisphere on each end, the total length of the tank is 16 feet. the width of the tank is 6 feet. he intends to paint the
I am looking the domain of g^2-6g-55/g. The denominator here can be also be written as 1g, right?
I have an algebra test tomorrow and still don''t understand how to simplify and solve radicals
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