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One integer is two more than another. The sum of the lesser integer and double the greater is 7. What is the greater integer?
Let x = the greater integer and y = the lesser integer. From the ?rst sentence within the question we get the equation x = y + 2. From the second sentence in the question we get y + 2x = 7. Substitute x = y + 2 within the second equation: y + 2(y + 2) = 7; use the distributive property to simplify to: y + 2y + 4 = 7. Combine like terms to obtain: 3y + 4 = 7; subtract 4 from both sides of the equation: 3y + 4 - 4 = 7 - 4. Simplify to 3y = 3.Divide both sides of the equation through 3: 3y/3 =3/3; thus y = 1. Since the greater is two more than the lesser, the greater is 1 + 2 = 3.
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1. Suppose n ≡ 7 (mod 8). Show that n ≠ x 2 + y 2 + z 2 for any x, y, z ε Z. 2. Prove ∀n ε Z, that n is divisible by 9 if and only if the sum of its digits is divisible by 9.
how do we figure it out here is an example 3,4,6,9,_,_,_,_,_,. please help
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Y=θ[SIN(INθ)+COS(INθ)],THEN FIND dy÷dθ. Solution) Y=θ[SIN(INθ)+COS(INθ)] applying u.v rule then dy÷dθ={[ SIN(INθ)+COS(INθ) ] dθ÷dθ }+ {θ[ d÷dθ{SIN(INθ)+COS(INθ) ] } => SI
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