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traverse the graph as BFS
For preorder traversal, in the worst case, the stack will rise to size n/2, where n refer to number of nodes in the tree. Another method of traversing binary tree non-recursively t
Let G=(V,E) be a graph for which all nodes have degree 5 and where G is 5-edge is connected. a) Show that the vector x which is indexed by the edges E and for which xe = 1/5 for
Example: Assume the following of code: x = 4y + 3 z = z + 1 p = 1 As we have been seen, x, y, z and p are all scalar variables & the running time is constant irrespective
#What is the pointer
Worst Case: For running time, Worst case running time is an upper bound with any input. This guarantees that, irrespective of the type of input, the algorithm will not take any lo
Here, m represents the unordered array of elements n represents number of elements in the array and el represents the value to be searched in the list Sep 1: [Initialize]
P os t - o r d e r T r av er sal : This can be done by both iteratively and recursively. The iterative solution would require a modification or alteration of the in-
AVL tree An AVL tree is a binary search tree in which the height of the left and right subtree of the root vary by at most 1 and in which the left and right subtrees are again
The time needed to delete a node x from a doubly linked list having n nodes is O (1)
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