Odd-even transposition algorithem, Computer Networking

Assignment Help:

Algorithm: Odd-Even Transposition

//Input: N numbers that are in the unsorted form

//Assume that element bi is assigned to pi

for I=1 to N

{

If (I%2 != 0) //i.e Odd phase

{

For j=1,3,5,7,..................2*n/2-1

{

Apply compare-exchange (Pj, Pj+1) //Operation is executed in parallel

}

}

Else // Even phase

{

For j=2,4,6,8..................2*(n-1)/2-1

{

} I++

}

 Apply compare-exchange(Pj, Pj+1) //Operation is executed in parallel

}

Let us take an example and illustrate the odd-even transposition algorithm.

Analysis

The above algorithm needs one „for loop? starting from I=1 to N, i.e. N times and for every value of I, one „for loop? of J is implemented in parallel. Thus, the time difficulty of the algorithm is O (n) as there are total n phases and each phase executes either odd or even transposition in O(1) time.

2417_Example.png

                                                                             Example


Related Discussions:- Odd-even transposition algorithem

Configure vtp on the switches - ccna, Configure VTP on the Switches VTP...

Configure VTP on the Switches VTP permits the network administrator to control the instances of VLANs on the network by creating VTP domains. Within each VTP domain, one or mor

Causes of failures, CAUSES OF FAILURES Every failure has a well-define...

CAUSES OF FAILURES Every failure has a well-defined cause.  Any system or device has an inherent strength or capacity to resist failures. This depends on design, material, man

Designing an internet work, 1. Introduction This document describes t...

1. Introduction This document describes the research-based assignment for this module. This assignment consists of two parts: A formal report And a presentatio

Calculate the efficiency of stop-and-wait ARQ, 5. Suppose that frames are 1...

5. Suppose that frames are 1250 bytes long including 25 bytes of overhead. Also assume that ACK frame are 25 bytes long. Calculate the efficiency of Stop-and-Wait ARQ in a system t

Udp segment structure - transport layer, UDP Segment Structure The  pr...

UDP Segment Structure The  primary  purpose  of the UDP protocols  is to expose datagram's to the application  layer. The UDP protocols does very  little and therefore  employ

Enumerate about the traffic policing, Enumerate about the Traffic policing ...

Enumerate about the Traffic policing Traffic policing happens when a flow of data is regulated so that cells (or frames or packets) that exceed a performance level are discarde

Explain about the digital traffic channels, Explain about the Digital traff...

Explain about the Digital traffic channels The most notable difference among the two generations is that first generation systems are almost purely analog, while second generat

Ack received - trasnport layer, ACK Received If an ACK is received by ...

ACK Received If an ACK is received by the  sender. The  SR sender marks  that packet  as having  been received by the receiver.

Routing table - network layer and routing , Routing Table Each  router ...

Routing Table Each  router now  uses the  shortest path tree to construct its routing table . each  router  uses the same algorithm and the same link state  database its own sh

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd