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If the areas of the circular bases of a frustum of a cone are 4cm 2 and 9cm 2 respectively and the height of the frustum is 12cm. What is the volume of the frustum. (Ans:44cm 2 )
Evaluate: 30 - 12÷3×2 =
i have many trouble in this subject
If the diameter of a right cylinder is doubled and the height is tripled, its volume is a. multiplied by 12. b. multiplied by 2. c. multiplied by 6 d. multiplied by 3.
sin(2x+x)=sin2x.cosx+cos2x.sinx =2sinxcosx.cosx+(-2sin^2x)sinx =2sinxcos^2+sinx-2sin^3x =sinx(2cos^2x+1)-2sin^3x =sinx(2-2sin^2x+1)-2sin^3
help solve these type equations.-4.1x=-4x+4.5
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