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A,B,C are natural numbers and are in arithmetic progressions and a+b+c=21.then find the possible values for a,b,c Solution) a+b+c=21 a+c=2b 3b=21 b=7 a can be 1,2,3,4,5,6 c c
assignment of mathematics in b.sc. 1sem
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what is the factor of the trinomial 2x2-7x-4
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