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Newton's Method : If xn is an approximation a solution of f ( x ) = 0 and if given by, f ′ ( xn ) ≠ 0 the next approximation is given by
xn+1 = xn - f(xn)/f'(xn)
It has to lead to the question of while do we stop? How several times do we go through this procedure? One of the more common stopping points in the procedure is to continue till two successive approximations agree upon a given number of decimal places.
y=f(a^x) and f(sinx)=lnx find dy/dx? Solution) dy/dx exist only when 0 1 as the function y = f(a^x) itself does not exist.
why zero factorial is equal to one
Q. Adding Fractions with the Same Denominator? Adding fractions with the same denominator is easy- you add the numerators (the tops), and you leave the denominator alone!
How to solve Brahmaguptas Problem? Explain Brahmaguptas Problem solving method?
3x2 +7x +4
Determine y′′ for x 2 + y 4 = 10 Solution: We know that to get the second derivative we required the first derivative and to get that w
Find out the number of ways in which 5 prizes can be distributed among 5 students such that (a) Each student may get a prize. (b) There is no restriction to the number o
how to make a tape diagram and a equivalent ratio
Derivative and Differentiation The process of acquiring the derivative of a function or slope or gradient is referred to as differentiation or derivation. The derivative is de
how many times can u put 10000 into 999999
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