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Newton's Method : If xn is an approximation a solution of f ( x ) = 0 and if given by, f ′ ( xn ) ≠ 0 the next approximation is given by
xn+1 = xn - f(xn)/f'(xn)
It has to lead to the question of while do we stop? How several times do we go through this procedure? One of the more common stopping points in the procedure is to continue till two successive approximations agree upon a given number of decimal places.
in and ap 1,2,3,4,5,6,7,8,9 11,12,13,14,15,16,17,18,19 and like that nonzzero digit find tn Solution) First break the ''n'' number in terms of 10''s power. For e.g if n=3259 wri
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Example for Comparison Test for Improper Integrals Example: Find out if the following integral is convergent or divergent. ∫ ∞ 2 (cos 2 x) / x 2 (dx) Solution
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