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Newton's Method : If xn is an approximation a solution of f ( x ) = 0 and if given by, f ′ ( xn ) ≠ 0 the next approximation is given by
xn+1 = xn - f(xn)/f'(xn)
It has to lead to the question of while do we stop? How several times do we go through this procedure? One of the more common stopping points in the procedure is to continue till two successive approximations agree upon a given number of decimal places.
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The law of cosines can only be applied to acute triangles. Is this true or false?
Identify the surface for each of the subsequent equations. (a) r = 5 (b) r 2 + z 2 = 100 (c) z = r Solution (a) In two dimensions we are familiar with that this
So far we have considered differentiation of functions of one independent variable. In many situations, we come across functions with more than one independent variable
The population of a city is observed as growing exponentially according to the function P(t) = P0 e kt , where the population doubled in the first 50 years. (a) Find k to three
define regular pyramid
If x = b y where both b > 0, x > 0, then we define y = log b x, which is read as "y is the log to the base b of x". This means that, log b x or y is the number to
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Find the sum of (1 - 1/n ) + (1 - 2/n ) + (1 - 3/n ) ....... upto n terms. Ans: (1 - 1/n ) + (1 - 2/n ) - upto n terms ⇒[1+1+.......+n terms] - [ 1/n + 2/n +....+
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