Mutual exclusion variable, Operating System

Assignment Help:

Since each thread has its own processing space therefore communication between threads will need to be done through a common global variable. Since multiple threads can access the same global variable this can leads to race condition. Therefore what we want is to protect the variable so that only one thread can access the variable at any time. In POSIX this is done via the mutual-exclusion variable, mutex. A mutex variable allow us to perform the lock/unlock action so that the critical section of the code can be protected.

A mutual exclusion variable is lock using the function call pthread_mutex_lock(&mutex_variable) and unlock using the function call pthread_mutex_unlock(&mutex_variable). When a mutex variable is locked any other thread attempt to lock it will be blocked and have to wait until the variable is being unlocked. A mutex variable is declared using the following syntax:

pthread_mutex_t mutex_variable=PTHREAD_MUTEX_INITIALIZER;

One problem of mutex is the possibility of deadlock if more than one resource is required for processing. Assume there are two mutexes in total being accessed by two separate threads. If each thread is allowed to lock only one of the two mutex that is required by each thread, then everything will be at a standstill while each thread wait for the other mutex to be unlocked. To see the effect of deadlock compile and run the program intro_mutex_deadlock.c. Does the thread terminate? The answer is no. It is because PrintProcess1 always lock mutex_lock_1 first then mutex_lock_2 while PrintProcess2 always does it in the reverse order. This is known as circular wait, which is one of the four necessary condition required for deadlock. Therefore when multiple mutex are involved the order of the mutex lock is very important. Modify the program so that PrintProcess2 lock the mutex in the same order as PrintProcess1. The deadlock should now be resolved and both threads can complete to termination.

(Note that this is one of the four conditions required for deadlock to occur: circular wait. As an exercise, list the other three necessary conditions for deadlock and identify which part of the intro_mutex_deadlock.c source code satisfies the condition. See if you can modify the program such that the deadlock can be avoided by eliminating each of the required condition.)


Related Discussions:- Mutual exclusion variable

Define action that implementing meaning of instruction, Determine how Actio...

Determine how Action implementing instruction’s meaning are a actually carried out   Action implementing meaning of instruction are a actually carried out Instruction executio

Tcp and ip stack, What does the last four digits '0010' of the above dump r...

What does the last four digits '0010' of the above dump represent? What action will the Destination node takes when it receives this packet? The last four digits '0010' denotes

Demand paging, Demand paging With demand paging, a page is called into...

Demand paging With demand paging, a page is called into memory only when a location on that page is actually indexed during run time. With pre-paging, pages other than the one

Define thrashing, Define thrashing. Thrashing is the accident of high p...

Define thrashing. Thrashing is the accident of high page traffic and low CPU utilization. It is observed that the cause of thrashing is an under-commitment of memory to program

How can an index file be used to speed up, How can an index file be used to...

How can an index file be used to speed up the access in direct-access files? Have an index in memory; the index gives the key and the disk location of its corresponding record.

Explain process state with diagram, Question 1 Explain single Partition Al...

Question 1 Explain single Partition Allocation and Multiple Partition Question 2 What is PCB? What useful information is available in PCB? Question 3 Explain Preemptive and No

Explain the various types of computer systems, Explain the various types of...

Explain the various types of computer systems. Mainframe systems Large Number of CPU with Greatest Processing Power:  Huge Memory Capacity:  Increased Performance by s

Inventory differences, What makes a Just-in-Time inventory system differ fr...

What makes a Just-in-Time inventory system differ from a traditional inventory system?

What is the benefits os co-operating process, What is the benefits OS co-op...

What is the benefits OS co-operating process? Information sharing. Computation speeds up. Modularity. Convenience.

Define local procedure call, Q. What kinds of services does the process man...

Q. What kinds of services does the process manager provide? Define local procedure call? Answer: The process manager offers services for creating and deleting and using proce

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd