Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Since each thread has its own processing space therefore communication between threads will need to be done through a common global variable. Since multiple threads can access the same global variable this can leads to race condition. Therefore what we want is to protect the variable so that only one thread can access the variable at any time. In POSIX this is done via the mutual-exclusion variable, mutex. A mutex variable allow us to perform the lock/unlock action so that the critical section of the code can be protected.
A mutual exclusion variable is lock using the function call pthread_mutex_lock(&mutex_variable) and unlock using the function call pthread_mutex_unlock(&mutex_variable). When a mutex variable is locked any other thread attempt to lock it will be blocked and have to wait until the variable is being unlocked. A mutex variable is declared using the following syntax:
pthread_mutex_t mutex_variable=PTHREAD_MUTEX_INITIALIZER; One problem of mutex is the possibility of deadlock if more than one resource is required for processing. Assume there are two mutexes in total being accessed by two separate threads. If each thread is allowed to lock only one of the two mutex that is required by each thread, then everything will be at a standstill while each thread wait for the other mutex to be unlocked. To see the effect of deadlock compile and run the program intro_mutex_deadlock.c. Does the thread terminate? The answer is no. It is because PrintProcess1 always lock mutex_lock_1 first then mutex_lock_2 while PrintProcess2 always does it in the reverse order. This is known as circular wait, which is one of the four necessary condition required for deadlock. Therefore when multiple mutex are involved the order of the mutex lock is very important. Modify the program so that PrintProcess2 lock the mutex in the same order as PrintProcess1. The deadlock should now be resolved and both threads can complete to termination.
(Note that this is one of the four conditions required for deadlock to occur: circular wait. As an exercise, list the other three necessary conditions for deadlock and identify which part of the intro_mutex_deadlock.c source code satisfies the condition. See if you can modify the program such that the deadlock can be avoided by eliminating each of the required condition.)
Q. Compare the utilization of networking sockets with the use of shared memory as a mechanism for communicating data between processes on a single computer. What are the merits of
explain about design issues of network operating system
Q. What are the three main activities of an operating system in regard to secondary-storage management? Answer: 1) Free-space management 2) Storage allocation 3) Disk
What is super block A partition control block have partitions details, such as the number of blocks in the partition, size of the blocks, free-blocks and free-block pointers an
Explain a working of file control block A file control block (FCB) has information about the file, containing ownership, permission, and location of the file contents. The log
Second-Chance algorithm When a page has been selected, we inspect its reference bit. If the value is 0, we proceed to replace this page. If the reference bit is set to 1, thoug
explain function of computer operating system?
Q. Operating System as User Interface? • Every general purpose computer comprises the operating system, hardware, system programs and application programs. The hardware compris
mention the three problems that mat be caused by wrong initialization and placement of wait() and signal()operations in the use of semaphore
what is segmentation as it refers to operating system
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd