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Multiplication Rule: Dependent Events
The joint probability of two events A and B which are dependent is equal to the probability of A multiplied by the probability of B given that A has occurred.
P(A and B) =P(A) P(B|A)
or P(B and A) =P(B) . P(A|B)
This formula is derived from the formula of conditional probability of dependent events.
P(B|A) =
Þ P(A and B) = P(B|A).P(A)
Example
A study of an insurance company shows that the probability of an employee being absent on any given day P(A) is 0.1. Given that an employee is absent, the probability of that employee being absent a second day in succession P(B|A) is 0.4. Events A and B are dependent events because B cannot occur unless event A has occurred. The probability of an employee being absent on two successive days
P(A and B) =P(A) . P(B|A)
=(0.1) (0.4) = 0.04
Thus, the probability of an employee being absent on two successive days is 0.04 or 4% of the time.
Joint probability of several dependent events is equal to the product of the probabilities of occurrence of the preceding outcomes in the sequence.
P(A and B and C...) = P(A) P(B|A) P(C|A and B) ....
In order to compute the inequalities of the form where n 1 , n 2 , ....... , n k , m 1 , m 2 , ....... , m p are natural and real numbers and a 1 , a 2 , ... , a k ,
How many integers satisfy (sqrt n- sqrt 8836)^2 Solution) sqrt 8836 = 94 , let sqrt n=x the equation becomes... (x-94)^2 (x-94)^2 - 1 (x-95)(x-93) hence 93 8649 the number o
railway tunnel of radius 3.5 m and angle aob =90 find height of the tunnel
what toold we need to study market
-9+f ?-1 ?? (a-1)=-12 f(-3)=2
Find the coordinates of the point P which is three -fourth of the way from A (3, 1) to B (-2, 5).
if 1/x+2, 1/x+3, 1/x+5 are in AP find x Ans 1/x+2,1/x+3, 1/x+5 are in AP find x. 1/x+3 - 1/x+2 = 1/x+5-1/x+3 => 1/x 2 +5x+6 = 2/ x 2 +8x +15 => On solving we get x
20% of $19.95
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2.3 8.8 3.5 4 5 _______,___/____________ ?
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