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Case 1: Suppose we have two terms 7ab and 3ab. When we multiply these two terms, we get 7ab x 3ab = (7 x 3) a1 + 1 . b1 + 1 ( Therefore, xm . xn = xm + n) = 21a2b2. The product of 7ab x 3ab will be the same as that of 3ab x 7ab. Irrespective of the order of multiplication, the product of two positive terms will be a positive term. Similarly, the product of 8a2b and 3a2b = (8 x 3) a2 . a2 b . b = 24 a2+2 b1+1 = 24 a4 b2 Case 2: Suppose we have to compute the product of -7ab and -3ab, it will be equal to (-7 x -3) a2b2 = 21a2b2, i.e. multiplication of two negative quantities gives us a positive quantity.
Case 1: Suppose we have two terms 7ab and 3ab. When we multiply these two terms, we get 7ab x 3ab = (7 x 3) a1 + 1 . b1 + 1 ( Therefore, xm . xn = xm + n) = 21a2b2. The product of 7ab x 3ab will be the same as that of 3ab x 7ab. Irrespective of the order of multiplication, the product of two positive terms will be a positive term.
Similarly, the product of 8a2b and 3a2b
= (8 x 3) a2 . a2 b . b
= 24 a2+2 b1+1
= 24 a4 b2
Case 2: Suppose we have to compute the product of -7ab and -3ab, it will be equal to (-7 x -3) a2b2 = 21a2b2, i.e. multiplication of two negative quantities gives us a positive quantity.
Let R be the relation on S = {1, 2, 3, 4, 5} defined by R = {(1,3); (1, 1); (3, 1); (1, 2); (3, 3); (4, 4)}. (b) Write down the matrix of R. (c) Draw the digraph of R.
the area of a triangle is 20 and its base is 16. Find the base of a similar triangle whose area is 45. Given is a regular pentagon. Find the measure of angle LHIK.
If ABC is an obtuse angled triangle, obtuse angled at B and if AD⊥CB Prove that AC 2 =AB 2 + BC 2 +2BCxBD Ans: AC 2 = AD 2 + CD 2 = AD 2 + (BC + BD) 2 = A
4856+12334
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To find out the perimeter of a triangular region, what formula would you use? The perimeter of a triangle is length of surface a plus length of side b plus length of side c.
The time t required to test a computer memory unit is directly proportional to the square of the number n of memory cells in the unit. For a particular type of unit, n = 6400
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