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Consider the following multiplication in decimal notations: (999).(abc)=def132 ,determine the digits a,b,c,d,e,f. solution)a=8b=6c=8d=8e=6f=7In other words, 999 * 877 = 876132.You don''t need to find out d,e,f, as they''re dependent. You only need to find out a,b,c.Now, start with c, because it''s in the ones place and thus easiest. What digit, when multiplied by 9, gives a "2" in the ones? The answer: 8. because 8 * 9 = 72. That the "2" you have there.Now we need to find out b. What digit, when multipled by 9, and added 9 (from the step above, the tens digit), gives a "4" in the ones? The naswer: 6. because 6 * 9 = 54, and added 9 to 4 gives us 13. That''s the "3" we have there. Now we need to find out c. what digit when multiplied with 9 and added 19 (from the step above) , gives a "1" in the ones..? the answer :8 because 8*9 = 72 and added 2 to 19 gives 21. that''s "1" we have therenow we have a=8 , b=6 , c=8 therefore we have 999*868=def132. multiply both the numbers and you get d, e and f..
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The alternative hypothesis When formulating a null hypothesis we also consider the fact that the belief may be found to be untrue thus we will refuse it. Therefore we formula
Let u = sin(x). Then du = cos(x) dx. So you can now antidifferentiate e^u du. This is e^u + C = e^sin(x) + C. Then substitute your range 0 to pi. e^sin (pi)-e^sin(0) =0-0 =0
y=f(a^x) and f(sinx)=lnx find dy/dx? Solution) dy/dx exist only when 0 1 as the function y = f(a^x) itself does not exist.
x2+y2 r=12
We know that the terms in an A.P. are given by a, a + d, a + 2d, a + 3d, ........ a + (n - 2)d, a + (n - 1)d The sum of all t
matrix of [1 4 ] [a b]=4/9
I need help with my homework, I am to the edge right now with this w=5pq/2
1) find the maxima and minima of f(x,y,z) = 2x + y -3z subject to the constraint 2x^2+y^2+2z^2=1 2)compute the work done by the force field F(x,y,z) = x^2I + y j +y k in moving
teach me how to o times 7s
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