Multiplication example, Mathematics

Assignment Help:

Example 

Multiply 3x5 + 4x3 + 2x - 1 and x4 + 2x2 + 4.

The product is given by

3x5 . (x4 + 2x2 + 4) + 4x3. (x4 + 2x2 + 4) + 2x .

(x4 + 2x2 + 4) - 1 . (x4 + 2x2 + 4)

= 3x5 . x4 + 3x5 . 2x2 + 3x5 . 4 + 4x3 . x4 + 4x3 .

2x2 + 4x3 . 4 + 2x . x4 + 2x . 2x2 + 2x . 4 - x4 - 2x2 - 4

To simplify the above we employ a rule which we will learn in laws of indices. It states that  xm . xn = xm+n

= 3x9 + 6x7 + 12x5 + 4x7 + 8x5 + 16x3 + 2x5 + 4x3 + 8x - x4 - 2x2 - 4  

Now we collect like terms and simplify them. We obtain 3x9 + 10x7 + 22x5 - x4 + 20x3 - 2x2 + 8x - 4.


Related Discussions:- Multiplication example

Cenamatic, a tire placed on a balancing machine in a service station starts...

a tire placed on a balancing machine in a service station starts from rest an d turns through 4.7 revolutions in 1.2 seconds before reaching its final angular speed Calculate its a

Calculate the density of people per square mile, 1.  In 1900, a certain cou...

1.  In 1900, a certain country's population was 77,977,459 and it's area was 2,821,924 square miles, In 2000, the country's population was 283,575,229 and its area was 3,551,003 sq

Retest Simulation, What is the probability of guessing five questions on a ...

What is the probability of guessing five questions on a test correctly

Objective type , when is the trnscribing process of data preparation irrele...

when is the trnscribing process of data preparation irrelevant ? a)CAPI b) mall panel c) in home interview d) all of them

Interval of validity, The interval of validity for an IVP along with initia...

The interval of validity for an IVP along with initial conditions: y(t 0 ) = y 0 or/and y (k) (t 0 ) = y k There is the largest possible interval on that the solution is va

Steps for radio test - sequences and series, Steps for Radio test Assum...

Steps for Radio test Assume we have the series ∑a n Define, Then, a. If L b. If L>1 the series is divergent. c. If L = 1 the series might be divergent, this i

Solve 4 cos(t )= 3 on[-8, Solve 4 cos(t )= 3 on[-8,10]. Solution : Here...

Solve 4 cos(t )= 3 on[-8,10]. Solution : Here the first step is identical to the problems in the previous section. First we need to isolate the cosine on one side by itself & t

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd