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Motorola 68000 Series :
68000microprocessor is a 16 bit processor that has addressing space of 65536 locations, each of which holds a 64-bits word; In order to address those locations, 16-bits operands are needed, 2 of which leave 32 bits free for other purposes; of these 32 bits, 16 are used to hold the op code.
68000 Architecture has Instruction :
SBB: Subtract with Borrow :- The subtract with borrow instruction subtracts the source operand and the borrow flag (CF) which might reflect the result of the past calculations,
write a program that calculates the fibonacci series: except for the first two numbers in the sequence
8279 Keyword /Display Controller : Figure shows the structure of 8279 and its interface to the bus. Addressing is according to the table given below. CS RD
Comparison between 8086 and 8088 All the changes in 8088 above 8086 are indirectly or directly related to the 8-bit, 8085 compatible data and control bus interface. 1) The p
This is a short program to practice assembly language loops and if/else statements. You will use various jump commands and the cmp instruction. The program will generate a random
CBW: Convert Signed Byte to Word: This instruction converts a signed byte to a signed word. In other terms, it copies the sign bit of a byte to be converted to all of the bits in
Write a nonrecursive version of the Factorial procedure (Section 8.3.2) that uses a loop. (A VideoNote for this exercise is posted on the Web site.) Write a short program that inte
How do i convert a asci number to numerals?
Signal descriptions of 8086 : described below are common for the maximum andminimum mode bothdata lines AD15 -AD0: These are the time multiplexed andmemory I/O address. Addre
Write a program to mask bits D3D2D1D0 and to set bits D5D4 and to invert bits D7D6 of ax register
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