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Motorola 68000 Series :
68000microprocessor is a 16 bit processor that has addressing space of 65536 locations, each of which holds a 64-bits word; In order to address those locations, 16-bits operands are needed, 2 of which leave 32 bits free for other purposes; of these 32 bits, 16 are used to hold the op code.
68000 Architecture has Instruction :
segmentation and overlapping in assemble language
Program: Write a program to perform addition of a series of 8-bit numbers. The series have 100 (numbers). Solution : In the first program, we have been implemented the add
DMA Hardware (8237 DMAC) : 1)Processor contain HOLD/HOLD Acknowledge lines to interact with 8237 o DMAC can achieve control of ISA bus by asserting HOLD o P
Ask 2. Exchange higher byte of AX and higher byte of BX registers by using memory location 0160 in between the transfer. Then stores AX and BX registers onto memory location 0174 o
The processor 8088 The launching of the processor 8086 is consider as a remarkable step in the development of high speed computing machines. Before the introduction of 8086 mo
need some project ideas
Zero flag: The next line compares the value in register. A with the value 1. If they are equivalent, the Zero flag is set (to 1). The next line then jumps to start: only if th
Data copy/transfer Instructions MOV: This data transfer instruction transfers data from one register or memory location to another register or memory location. The source can
1. Start your program at address $8500. To do this you need to inform the assembler, through the EQU and ORG assembler directives, that you want your program to start at $8500. Thi
Problems: 1. Write a single program. Each of the problems (2-4) should be written within a procedure. Your “main” procedure should call each procedure. Before calling each proc
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