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Moment of Disk or Solid Cylinder about Axis
We presume the axis of rotation is perpendicular to the disk and through its center and coincident with the axis of the cylinder. Consent the radius of the disk be R and a mass element δm = σδS. A surface element is able to be defined as δS = r dθ dr. Alternative the surface element
Into the equation for a mass element we have δm = σr dr dθ. Since an element of inertia is able to be expressed δI = δmr2 we are able to write
δI = σr2rδr δθ and,
δI = σr3δr δθ
Summing the elements and taking limits confer
Performing the integrations
I = σ2π(R4/4)
I = σπ(R4/2).
The mass of the disk is σπR2
I =1/2(mR2).
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