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We here move to one of the major applications of differential equations both into this class and in general. Modeling is the process of writing a differential equation to explain a physical situation. Mostly all of the differential equations which you will use in your job as for the engineers out there in the audience are there since somebody, at several time, modeled a situation to come up along with the differential equation which you are using.
In this section is not intended to wholly teach you how to go regarding to modeling all physical situations. A complete course could be dedicated to the subject of modeling and even not cover everything! This section is implemented to introduce you to the method of modeling and demonstrate you what is included in modeling. We will seem three different situations in this section as: Falling Bodies, Population Problems and Mixing Problems.
In these all of situations we will be forced to create assumptions that do not correctly depict reality in most cases, but without them the problems would be extremely difficult and beyond the scope of such discussion and also the course in most cases to be truthful.
use the expansion of (1-x)^7 to find the value of 1.998^7 correct to five significant figures
One of the simplest physical situations to imagine of is a falling object. Thus let's consider a falling object along with mass m and derive a differential equation as, when resolv
There are five horseracing tracks in Kentucky. The Kentucky legislature allows only one track to be open at a time. How does this restriction affect the price the track can charge
Cylindrical Coordinates - Three Dimensional Space Since with two dimensional space the standard (x, y, z) coordinate system is known as the Cartesian coordinate system. In the
define algorithm of pert and pert with suitable examples
Arc Length with Polar Coordinates Here we need to move into the applications of integrals and how we do them in terms of polar coordinates. In this part we will look at the a
x=+y^2=4
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Let's here start thinking regarding that how to solve nonhomogeneous differential equations. A second order, linear non-homogeneous differential equation is as y′′ + p (t) y′ +
( a+2b)x + (2a - b)y = 2, (a - 2b)x + (2a +b)y = 3 (Ans: 5b - 2a/10ab , a + 10b/10ab ) Ans: 2ax + 4ay = y , we get 4bx - 2by = -1 2ax+ 4ay = 5 4bx- 2by = - 1
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