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Mode 2
In this mode transistor gets turned off by the negative output of PWM current flows through inductance L diode D then divide into two parts one flows through capacitor C and other load. In this condition the magnetic field in the inductor collapses and induces a large voltage across the coil of opposable polarity.
That adds to the input voltage capacitor C will charge through this current and maintain the o/ p voltage when transistor gets turned on for next cycle.
Now that you have the input and output impedances you can design the matching networks. I will require either the Smith Charts showing how you calculated the matching components or
Simulation of a pn Junction An n + p junction is fabricated on a p-type silicon substrate with N A = 8×10 15 cm -3 . The n+ region has a concentration of N D = 1.5×10 18
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