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Mode 2
In this mode transistor gets turned off by the negative output of PWM current flows through inductance L diode D then divide into two parts one flows through capacitor C and other load. In this condition the magnetic field in the inductor collapses and induces a large voltage across the coil of opposable polarity.
That adds to the input voltage capacitor C will charge through this current and maintain the o/ p voltage when transistor gets turned on for next cycle.
what is use of capacitance calculation
Hai.. i have been given a open loop transfer function to draw a bode plot with a particular K value and they asked me to find the value of K for which the phase margin becomes 45d
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Consider the circuit of Figure (a), including a dependent source. Obtain the Thévenin equivalent at terminals a-b.
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is electrical power more important in the world than other streams?
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