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Minimise the logic function F (A, B, C, D) = Π M (1, 2, 3, 8, 9, 10, 11,14) ⋅ d (7, 15)Use Karnaugh map. Ans. Given function F=∏M(1,2,3,8,9,10,11,14).d(7, 15)F'=B'D+B'C+AC+AB' By Complementing FF=(B'D+B'C+AC+AB')'= [(B'D)'(B'C)'(AC)'(AB')']'= (B+D')(B+C')(A'+C')(A'+B)Taking here complement twice but also without opening the bracketF=[(B+D')+(B+C')'('A'+C')+(A'+B)]'
Explain the differences of casex and casez over the case statement? casex operator has to be used when both high impedance value (z) and unknown (x) in any bit has to be t
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