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Since a controlled source acts at its terminals in the same manner as does an independent source, source conversion and application of KCL and KVL relations are treated identically for both types of sources. Because the strength of a controlled source depends on the value of a voltage or current elsewhere in the network, a constraint equation is written for each controlled source. After combining the constraint equations with the loop or nodal equations based on treating all sources as independent sources, the resultant set of equations are solved for the unknown current or voltage variables.
Equal volumes of all gases contain the samenumber of molecules when the volumes are measured at the same p and T. Therefore for a given volume at the same p and T, with the same
What is the difference between the shifts and rotate instructions? A rotate instruction is a closed loop instruction. That is, the data moved out at single end is put back in a
how do you work it out if there are 3 sources in parallel?
While sitting in physics class one day, you begin to ponder the workings of the analog clock on the classroom wall. You notice as the hands sweep in a continuous motion that there
1. A very narrow laser beam in air is shone into a sphere of solid glass that has a uniform refractive index n>1 and radius ? . The beam makes an angle a in air with the normal to
Hi, I got assignment to design a power electronic system Design the circuit and select the appropriate components for that circuit to fulfil the requirements of the device. Regards
1. The rejection criteria of an investment project, as evaluated from the NPV method is that NPV should be equal to zero. 2. Technical feasibility is the only criteria to dete
Q. Common-Emitter Configuration? The emitter part of a circuit being common to both the input and the output portions, Figure (a) illustrates a common-emitter (CE) BJT amplifie
Using Bode plot calculate (a) Phase margin (b) Gain margin (c) Stability of closed loop system. The open transfer function of the system is t=30/(s+2)/(s+3)Using Bode plot calcula
Why we provide the short circuit and open circuit test in transformer
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