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Since a controlled source acts at its terminals in the same manner as does an independent source, source conversion and application of KCL and KVL relations are treated identically for both types of sources. Because the strength of a controlled source depends on the value of a voltage or current elsewhere in the network, a constraint equation is written for each controlled source. After combining the constraint equations with the loop or nodal equations based on treating all sources as independent sources, the resultant set of equations are solved for the unknown current or voltage variables.
cosider a causal LTI system whose system function is H(z)=1-1/5z^-1/(1-1/2z^-1+1/3z^-2)(1+1/4z^-1) find the direct form 1 and direct form 2
Q. A voltmeter with a full scale of 100 V has a probable error of 0.1% of full scale. When this meter is employed to measure 100 V, find the percent of probable error that can exis
Explain the Sequential Circuits? The Logic circuits whose outputs, at any instant of time, depends not merely the present input but as well the past output called sequential ci
advantages and disadvantages of direct and r c coupling
Q. Explain a Tube Well? Method of restoring or increasing the capacity of tube well is known as developing a Tube Wells. This is done to eliminate bridging of fine particles on
Write a program implementing the conjugate gradient method (un-preconditioned). Solve the matrix equation corresponding to a finite difference node-spacing, h = 0.02m in x and y di
Define Spectrum of Real Signals? In the real world, we rarely come throughout a pure sine wave. Typical signals have a wide spectrum as displayed in the above diagram. Informat
Q. Working of Microprocessor Control? The microprocessor, which has rapidly become a key component in digital control systems, and its associated circuits function as the digit
A switch-mode power supply is to be designed with the following specifications: input voltage V s = 48 V ± 10%, output voltage V o = 5 V, switching frequency f s = 100 kHz, outp
Q. Do as directed. a) Hexadecimal addition: 101 + ABC b) (43.25) 10-(89.75) 10 using 1's Complement c) Octal Subtraction 123-777 d) (123)6 + (435)6 = ( ? )6 e) ABC
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