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Memory Interface
Figure: Memory Modulation design
The memory of a computer contain of number of memory modules. Each module consists of an array of memory IC devices and an interface. Each IC device consists of an array of memory cells as shown in given fig. Each cell may store 1 bit.
Microprocessor do communicates with memory through memory interface.The primary function of memory interface is that the microprocessor might be able to write or from read to a given register of memory chip. The microprocessor might be able to choose the memory chip, send control signals for write or read operation. Certain signals to denote whether a Memory write or read operation has to be performed. Whenever a communication with memory is needed, a set of signals has to be sent by CPU.
Chip choose logic which is utilized to choose the specific chip based on the signal it receives from the transceiver.
Interrupt System Based on Single 8259 A The 8259A is contained in a 28-pin dual-in-line package that need only a + 5-V supply voltage. Its organization is shown in given figur
Program: Write a program to perform addition of a series of 8-bit numbers. The series have 100 (numbers). Solution : In the first program, we have been implemented the add
XOR: Logical Exclusive OR: The XOR operation is again carried out in a similar way to the AND and OR operation. The constraint over operands are also similar. The XOR operation pr
Convert 751 to hex and show what it would look like stored at TheNumber WORD ? (hint: answer in hex pairs)
1. Start your program at address $8500. To do this you need to inform the assembler, through the EQU and ORG assembler directives, that you want your program to start at $8500. Thi
.MODEL SMALL .STACK 100H .DATA PROMPT DB \''The 256 ASCII Characters are : $\'' .CODE MAIN PROC MOV AX, @DATA ; initialize DS MOV DS, AX
Internal Hardware-Interrupts Internal hardware-interrupts are the outcome of sure situations that occur during the execution of a program, for example. Divide by 0. The interru
Segment Registers The 8086 addresses a segmented memory unlike 8085. The complete 1 megabyte memory, which 8086 is capable to address is divided into 16 logical segments.Thusea
Write a program to do the following: 1. Print your name 2. Using a bottom testing loop, prompt the user to enter a number from 1 to 5. If the number entered is not 1..5, pri
init_lcd ;(this initialises a 2 row lcd) bcf TRISA,0 ;PORTA bit 0 as an output (lcd RS pin) bcf TRISA,1 ;PORTA bit 1
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