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Memory Interface
Figure: Memory Modulation design
The memory of a computer contain of number of memory modules. Each module consists of an array of memory IC devices and an interface. Each IC device consists of an array of memory cells as shown in given fig. Each cell may store 1 bit.
Microprocessor do communicates with memory through memory interface.The primary function of memory interface is that the microprocessor might be able to write or from read to a given register of memory chip. The microprocessor might be able to choose the memory chip, send control signals for write or read operation. Certain signals to denote whether a Memory write or read operation has to be performed. Whenever a communication with memory is needed, a set of signals has to be sent by CPU.
Chip choose logic which is utilized to choose the specific chip based on the signal it receives from the transceiver.
Read Architecture: Look Through Main memory that located is conflicting the system interface. The least concerning feature of this cache unit is that it remain between the proc
DMA DMA stands for Direct Memory Access It is uses same Address/Data lines on ISA bus It controls the ISA bus instead of the processor ("bus master") Floppy
LIST p=18f4550 #include org 0x0000 movlw 0x00 _________ movlw 0xFF movwf PORTB end .
;StrNCpyAsm - copy zero terminated string2 to zero terminated string1, ; but copy no more than count (parameter) characters ; or the length of string2, whi
You have to write a subroutine (assembly language code using NASM) for the following equation. Dx= ax2+(ax-1)+2*(ax+2)/2
Assume that the registers are initialized to EAX=12345h,EBX =9528h ECX=1275h,EDX=3001h sub AH,AH sub DH,DH mov DL,AL mov CL,3 shl DX,CL shl AX,1 add DX,AX
Intel 8259 interrupt controller : The 8088 processor has only two interrupt control inputs, and interrupt request (INTR) and non mask able interrupt (NMI). NMI are interrupts t
Write a program that allows a user to encrypt/decrypt a message using a shift cipher. The user should specify the key and the message. Your program should be able to handle messa
Mov ax, [1234h: 4336h + 100]
Example : Add the contents of the 2000H: 0500H memory location to contents of 3000H: 0600H and store the result in 5000H: 0700H. Solution : Unlike the past example progra
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