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Computation method
Whereas L = Lower class boundary of the class having the mode
f0 = Frequency of the class below the modal class
f1 = Frequency of the class having the mode
f2 = frequency of the class above the modal class
c = Class interval
Hence mode = 60.50 +[(48 - 32)/{{2(48)} - 32 -27}] * 20
= 69.14
If the hight of pipe is 18 inches, what is the volume of the shaded region in terms of π? a. 31.5π in 3 b. 126π in 3 c. 157.5 in 3 d. 58.5 in 3
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