Measure and set frequency by using an oscilloscope, Electrical Engineering

Assignment Help:

1. Introduction:

Theory: Frequency is the number of occurrences of a repeating event per unit time. It can also be defined as the number of repetitions (cycles) of a waveform that appear in a one second. It is very important to measure the frequency of a waveform passed through a circuit used in various electronic gadgets. The frequency can be measured using the oscilloscope using the formula,

F= 1 / T

Hence, if the Time period (T) gets measured, the frequency also can be calculated. Time period is defined as the duration between two adjacent repeating events.

Material Required: Oscilloscope, frequency generator, connecting wires.

Description and Aim: To measure and set frequency by using an oscilloscope.

The frequency is fed into the oscilloscope by using a generator. Hence, oscilloscope will show the frequency signal on a visual display. The oscilloscope display is adjusted so that a clear wave form is seen on the display. The time period is calculated from this waveform.

F = 1/T

2. Method:

Step 1) Use terminal ports to connect generator to DC/AC waveforms circuit block. Now, use two port connector to connect generator source to R1.

Step2) From the generator, set frequency = 1Hz roughly, and select the sine wave. To calibrate the frequency, use dial setting properly. Now, connect channel 1 probe of oscilloscope across the resistor R1. Adjust generator amplitude so that

V(R1) = Vpk-pk = 6 V

Step 3) Set time base control = 0.1 ms/div. Adjust the frequency of generator for a waveform cycle that is seven divisions wide on the horizontal axis (time axis). Measure the no of divisions on the oscilloscope display.

3. Results: (check the readings.. it shud be close to 1 hz as you have set a rough reading of 1 HZ in generator...for that you can change the no of measured time divisions to 8....also note down the unit of signals...was it mHz or Hz)

Vpk-pk = 6 V

No of time divisions for one waveform = 7

One time division = 0.1ms/div

Total time period  = 7 * 0.1 = 0.7 ms

Frequency = F = 1 / T = 1 / 0.7  = 1.42 Hz.

4. Discussion:

The frequency measured using the oscilloscope is 1.42Hz.  This frequency is close to the frequency signal from the generator as the dial was set to 1 Hz roughly. There is a difference between the two frequencies due to reasons like attenuation in the circuit components, degree of accuracy to measure width of waveform on oscilloscope (i.e. divisions in waveform), fluctuations in the generator etc. To precisely read the circuit we can set the signal more accurately in the generator using dial up knob and then measure the time period at oscilloscope.


Related Discussions:- Measure and set frequency by using an oscilloscope

Apply required morphological operations and give the output, You are given ...

You are given a binary image consisting of only zeros and ones, see image-A. Apply required morphological operations and give the output images on the grid.

Radiation intensity pattern of antennas, Q. Radiation intensity pattern of ...

Q. Radiation intensity pattern of Antennas? Antennas do not radiate power equally in all directions in space. The radiation intensity pattern describes the power intensity (whi

Stack operation, Stack Operation Stack is a group of memory  locations...

Stack Operation Stack is a group of memory  locations which  are part of the  same read write memory  used for  storing  data  temporarily  during the execution of the  progra

Electrocardiogram, i av designed my circuit in proteus and written the java...

i av designed my circuit in proteus and written the java graphical code for analysis of the results....i need help on how i can run this circuit in proteus and get the results in t

CRT, Why are the operating voltages of a CRT arranged so that the deflectio...

Why are the operating voltages of a CRT arranged so that the deflection plates are nearly at ground potential?

Find maximum probable percentage error in the measurement, Q. A current of ...

Q. A current of 65 A is measured with an analog ammeter having a probable error of ± 0.5% of full scale of 100 A. Find the maximum probable percentage error in the measurement.

Explain about common control, Q. Explain about Common Control? Common C...

Q. Explain about Common Control? Common Control: Those systems in which the control subsystem is outside the switching network are known as common control switching system. Str

Nor gate - introduction to microprocessors , NOR Gate NOR means NOT OR ...

NOR Gate NOR means NOT OR . it complements the  output  of an OR  gate.  The symbol  of Nor  gate in fig. (a) shows that a Nor  gate  comprises  of an OR  gate followed  by a N

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd