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Here we need to see the inverse of a matrix. Provided a square matrix, A, of size n x n if we can get the other matrix of similar size, B that,
AB = BA = In after that we call B the inverse of A and denote it by B=A-1.
Calculating the inverse of a matrix, A, is quite simple. Firstly we form a new matrix,
(A In)
And after that use the row operations from the earlier section and try to change this matrix in the form,
(In B)
If we can so B is the inverse of A. If we can't so there is no inverse of the matrix A.
Proof of Alternating Series Test With no loss of generality we can assume that the series begins at n =1. If not we could change the proof below to meet the new starting place
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how to explain this strategy? how to do this strategy in solving a problem? can you give some example on how to solve this kind of strategy.
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