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Let u = sin(x). Then du = cos(x) dx. So you can now antidifferentiate e^u du. This is e^u + C = e^sin(x) + C. Then substitute your range 0 to pi. e^sin (pi)-e^sin(0) =0-0 =0
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Geometric Applications to the Cross Product There are a so many geometric applications to the cross product also. Assume we have three vectors a → , b → and c → and we make
Prove that, the complement of each element in a Boolean algebra B is unique. Ans: Proof: Let I and 0 are the unit and zero elements of B correspondingly. Suppose b and c b
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Hyperbolic Paraboloid- Three Dimensional Space The equation which is given here is the equation of a hyperbolic paraboloid. x 2 / a 2 - y 2 / b 2 = z/c Here is a dia
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