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what is the diameter of a circle

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Equivalence class and equivalence relation, 1. For a function f : Z → Z, le...

1. For a function f : Z → Z, let R be the relation on Z given by xRy iff f(x) = f(y). (a) Prove that R is an equivalence relation on Z. (b) If for every x ? Z, the equivalenc

Expert , i want to work with you, please guide me

i want to work with you, please guide me

Probability, You''ve decided you want a plant for your room. At the gardeni...

You''ve decided you want a plant for your room. At the gardening store, there are 444 different kinds of plants (tulip, fern, cactus, and ficus) and 444 different kinds of pots to

Mount everest is 29, Mount Everest is 29,028 ft high. Mount Kilimanjaro is ...

Mount Everest is 29,028 ft high. Mount Kilimanjaro is 19,340 ft high. How much taller is Mount Everest? Subtract Mt. Kilimanjaro's height from Mt. Everest's height; 29,028 - 19

Trigonometry, If a+b+c = 3a , then cotB/2 cotC/2 is equal to

If a+b+c = 3a , then cotB/2 cotC/2 is equal to

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use an expression to write an expression with five 3s that has a value of 0

Draw tangent graph y = sec ( x ), G raph y = sec ( x ) Solution: As wi...

G raph y = sec ( x ) Solution: As with tangent we will have to avoid x's for which cosine is zero (recall that sec x =1/ cos x) Secant will not present at

Math Help, 1. Which of the following is greater than 4.3 x 10^9 a. 2.1 x ...

1. Which of the following is greater than 4.3 x 10^9 a. 2.1 x 10^9 b. 3.2 x 10^9 c. 5.3 x 10^9 d. 7.4 x 10^8 2. Which of the following is less than 6.5 x 10^-5 a. 1.4 x 10

Evaluate the area of the shaded region, Evaluate the area of the shaded reg...

Evaluate the area of the shaded region in terms of π. a. 8 - 4π b. 16 - 4π c. 16 - 2π d. 2π- 16 b. The area of the shaded region is same to the area of the squa

Standard basis vectors -application of scalar multiplication, Standard Basi...

Standard Basis Vectors Revisited In the preceding section we introduced the idea of standard basis vectors with no really discussing why they were significant.  We can now do

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