Math Lessons, Mathematics

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Pre-calculus, finding the vertex for the function of the form f(x)=ax^2+bx...

finding the vertex for the function of the form f(x)=ax^2+bx+c

How mathematical ideas grow, HOW MATHEMATICAL IDEAS GROW :  In this sectio...

HOW MATHEMATICAL IDEAS GROW :  In this section we shall consider three aspects of the nature of mathematical ideas, namely, that they progress from concrete to abstract, from part

Show that tan = 1/v3 , If 7sin 2 ?+3cos 2 ? = 4, show that tan? =   1/√3  ...

If 7sin 2 ?+3cos 2 ? = 4, show that tan? =   1/√3                      . Ans:    If 7 Sin 2 ? + 3 Cos 2 ? = 4 S.T. Tan?  1/√3 7 Sin 2 ? + 3 Cos 2 ? = 4 (Sin 2 ? + Cos 2 ?)

Partial fraction decomposition - integration techniques, Partial Fraction D...

Partial Fraction Decomposition The procedure of taking a rational expression and splitting down it into simpler rational expressions which we can add or subtract to get the ori

Domain of a vector function - three dimensional space, Domain of a Vector F...

Domain of a Vector Function There is a Vector function of a single variable in R 2 and R 3 have the form, r → (t) = {f (t), g(t)} r → (t) = {f (t) , g(t), h(t)} co

Calculate time interval, From top of a tower a stone is thrown up and it re...

From top of a tower a stone is thrown up and it reaches the ground in time t1. A second stone is thrown down with the same speed and it reaches the ground in t2. A third stone is r

Important points about the alternating series test, Important Points About ...

Important Points About the Alternating Series Test There are a several things to note about this test.  Very first, unlike the Integral Test and the Comparison or Limit Compari

Find the greatest number of 6 digits exactly divisible by 24, Find the grea...

Find the greatest number of 6 digits exactly divisible by 24, 15 and 36. (Ans:999720) Ans: LCM of 24, 15, 36 LCM = 3 × 2 × 2 × 2 × 3 × 5 = 360 Now, the greatest six digit

Testing the hypothesis equality of two variances, Testing the hypothesis eq...

Testing the hypothesis equality of two variances The test for equality of two population variances is based upon the variances in two independently chosen random samples drawn

Trigonometry, Prove: 1/cos2A+sin2A/cos2A=sinA+cosA/cosA-sinA

Prove: 1/cos2A+sin2A/cos2A=sinA+cosA/cosA-sinA

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